After re-reading I still fail to understand your contact point thought, but is it merely to produce a magnetic field in the shaft? If we used a magnetized shaft, north at one end south at the other would this still be required to create the effect?
Is the force you are envisioning one that puts a torque on the individual ball bearings? Ah, maybe that's what you mean? On Sat, Jun 27, 2009 at 8:51 AM, John Berry <[email protected]> wrote: > A few thoughts, btw I have not fully comprehended everything you've said > yet but I'll have a crack at it... > From the stationary view point a magnetic dipole would be created only if > electron drift tended not to spiral. > The magnetic field would be generated by the rotating protons .vs non > spiraling electrons. > > Ok, so it generates a magnetic field dipole and a force would be on the > ball bearings but it would be equal and opposite at each end and so cancel. > > And any force placed on the shaft would be likewise canceled, for instance > if we assume that the shaft has a dipole field which seem plausible the > current cutting along the north end of the field would generate the opposite > force to that created by the south end. > > I don't yet follow the retarding metal contact point idea so I can't > comment. > > > On Sat, Jun 27, 2009 at 8:18 AM, William Beaty <[email protected]> wrote: > >> On Thu, 25 Jun 2009, William Beaty wrote: >> > One thing about self-excited electric motors of all kinds: they work >> > independantly of voltage polarity. >> >> >> WOW! I got it, I got it! >> >> In a ball bearing motor, if the path of current is spiral, then it creates >> a magnetic dipole field on axis with the bearing. If this happens, then a >> ball bearing race becomes a Faraday Homopolar motor/generator, with no >> field-magnet needed. And regardless of current polarity, the motor would >> always produce torque in the same direction (the direction determined by >> the spiral.) >> >> But WHY would the current be spiralling? >> >> Maybe the motion of the moving metal will bias the path of the amperes? >> >> On the other hand, if a ball bearing has a micro-layer of lubricant and >> corrosion, then it takes time to squeeze out this material as the bearing >> rolls forward. Therefore the contact point on the metal is retarded a bit >> when compared to an unmoving bearing. At higher RPM, the retarded >> position of the contact point would become greater, so torque would >> increase with RPM. Also, the metal/metal bond might persist for a bit >> before rupturing, also retarding the contact point. >> >> OK so far, but there could be a problem. If the direction of the slight >> spiral path is wrong, when compared to the direction of rotation, then the >> motor-effect will be in the wrong direction. The motor won't spin, >> instead it will act like a brake. >> >> I just worked it out with simple right-hand-rule issues. The force is in >> the correct direction! It doesn't matter whether it's CW or CCW. As long >> as the contact point gets retarded by the corrosion layer, it should >> accelerate the rotor. Coooool! >> >> But that means... a liquid-wetted version would eliminate the squeezed >> layer of crap, and it might have zero torque. (Or, perhaps the "tail" of >> liquid gallium might provide a more asymmetrical path, and increase the >> torque?) ...or if the whole thing was caused by thermal effects and >> expanded metal "bumps," the liquid-wetted version should stop working. >> >> In any case, it should be easy to build a motor by replacing the ball >> bearings with perfectly symmetrical slip rings, then welding some >> spiral-shaped bars between this bearing and the outer metal tube. Or even >> use some strips of sheet copper, insulated with paint, wrapped around the >> shaft to make a simple coil between the shaft and the copper pipe. >> >> EVEN BETTER: if this device is spun faster than its "natural" speed, it >> should become a generator and start recharging its battery. (Add some >> more RPMs to replace the wattage lost in the slip rings.) If the battery >> is replaced by a short, at some RPM threshold the ball bearings should >> produce a huge current and a magnetic field. A tiny benchtop Earths-core >> simulator! >> >> >> PS >> >> The moving balls have a vortex-like motion, where the metal is moving much >> faster in the center than at the outer edge. If the spiral path of amps >> was mostly caused by this vortex, then the entire ball bearing could be >> replaced by a pool of liquid mercury, and the motor would still produce >> the same torque. But if the spiral path is produced by corrosion layers, >> then a pool of liquid mercury would produce zero torque. >> >> >> >> That's why they're called "AC/DC" >> > motors. Self-excited homopolar generators DON'T put out one polarity >> for >> > CCW and a different polarity for CCW. Instead the polarity depends on >> > initial microscopic currents (much like Kelvin Thunderstorm Device with >> > microscopic voltage.) >> > >> > If Marinov's motor runs in the direction of its initial spin, it could >> > still be a Homopolar Faraday motor of the self-excited type. If spun >> > fast and shorted out, it might even become a Homopolar self-excited >> > generator, and produce an enormous current. >> > >> > >> > >> > (((((((((((((((((( ( ( ( ( (O) ) ) ) ) ))))))))))))))))))) >> > William J. Beaty SCIENCE HOBBYIST website >> > billb at amasci com http://amasci.com >> > EE/programmer/sci-exhibits amateur science, hobby projects, sci fair >> > Seattle, WA 206-762-3818 unusual phenomena, tesla coils, weird sci >> > >> >> (((((((((((((((((( ( ( ( ( (O) ) ) ) ) ))))))))))))))))))) >> William J. Beaty SCIENCE HOBBYIST website >> billb at amasci com http://amasci.com >> EE/programmer/sci-exhibits amateur science, hobby projects, sci fair >> Seattle, WA 206-762-3818 unusual phenomena, tesla coils, weird sci >> >> >
