Can you evaluate the costs of enrichment?

On Sat, May 7, 2011 at 9:47 AM, Axil Axil <janap...@gmail.com> wrote:

> Explaining Rossi.
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> Rossi said: “We think that all the Ni participates to the reactions, even
> if some isotopes should be more efficient.” “Only Ni 62 and Ni64 react.”
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> Rossi enriches his nickel in Ni62 and Ni64. Why? Through experimentation,
> Rossi found these isotopes performed best. But what is the theory behind
> this result?
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> Nickel-62 is an isotope of nickel having 28 protons and 34 neutrons. It is
> a stable isotope, with the highest binding energy per nucleon of any known
> nuclide (8.7945 MeV). The high binding energy of nickel isotopes in general
> makes nickel an "end product" of many nuclear reactions (including neutron
> capture reactions) throughout the universe and accounts for the high
> relative abundance of nickel and nickel-60 (the second-most, with the other
> stable isotopes (nickel-61, nickel-62, and nickel-64) being quite rare).
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> Nickel is the least likely element to participate in a fusion reaction.
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> If atomic holes are the place where the Rossi reaction occurs, Rossi wants
> a very strong and stable support structure that can provide a three
> dimensional quantum box that can produce the reaction.
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> Under the assumption that only hydrogen reacts in the quantum box and that
> many hydrogen atoms are fused in the Rossi reaction; the packing of all
> those hydrogen atoms into the lattice defects of nickel is a stressful
> process. If this nickel built Heisenberg box were to fail or fail apart
> during the packing of hydrogen, then the reaction will fail.
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> Nickel is the most stable element because its binding energy is maximized
> among the elements. The nickel isotopes that are the most stable are Ni62
> and Ni64. Rossi enriches his nickel in these most stable and stout isotopes
> because they can best support the atomic defects he uses to produce atomic
> events without blowing the lattice defects apart during the stresses of the
> atomic reactions and were nickel garbage would poison the pure hydrogen  
> reaction.
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> Elements on either side of nickel will perform best because of their very
> high binding energies.
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-- 
Dr. Peter Gluck
Cluj, Romania
http://egooutpeters.blogspot.com

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