I used another method, so, let's see: Considering that the hose is a black body in equilibrium, let's use the Stephan-Boltzman law, we have that the power per unit of area of the hose is 5.67×10-8 * (373k)^4 = 19.2* 10^9*5.67*10^-8= 1088.64 Watt/m^2 . The diameter of the hose seems to be 2cm, so the area of the hose is about 3m*3.14*0.02m= 0.18. So, the irradiated power is about 0.18*1088= 195.8W. The abosrbed by the evironment is 5.67×10-8 * (303k)^4 = 8.4*10^9 *5.67*10^-8 = 476.28W (the temperature of the lab is around 30C by the time of the video). So the abosorbed power is 0.18*476.28= 85.68W. So, the total power power ballance is 110W.
Given that this is quite not a black body, the value should be lower. That guy got 87.5 using another method.So perhaps there is a lot of cooling by convection?
