Craig, indeed that is true, liquid water does not contribute to the pressure at all, because water does not gently flow out of the E-Cat, but is spilled due to rather violent boiling at kW range in closed container.
Only thing that contributes for the pressure is steam flow pressure out of the E-Cat and in the hose. Steam flow resistance is roughly the same in all E-Cat setups, therefore steam temperature is depended directly and comparably on total water heating power. It was well established that wetness of the steam was something in order of 1-2% that is typical for normal boiling in closed container where there is lots of spilling and water droplet density is high. —Jouni Ps. Craig, although Joshua's ultrawet steam is crack pot theory, he is right, because 90% steam is not dense at all, but you measured it volumetrically, i.e. you kept the volume constant. But do not play Joshua's own game, because as discusser, he is a perpetual motion machine, whose purpose is to flood as much as possible so that any meaningful discussion is overflown. Volumetric measurement is completely irrelevant, because it depends heavily on pressure. On Jul 22, 2011 2:00 PM, "Damon Craig" <decra...@gmail.com> wrote: > The steam temperature is not measure at the location of evolution but futher > along in the device toward the exit. > > For those of us adhering to the Water Flow-though Hypothesis, the > thermometer is further toward the water surface at the height of the outlet > where the pressure is less than that where it originates. > > > On Thu, Jul 21, 2011 at 12:14 PM, Joe Catania <zrosumg...@aol.com> wrote: > >> I think the topology of the E-Cat would reveal alot about its >> characteristics as a boiler. But one thing is for sure: it would seem that >> the metal surface which gives rise to the steam is under some mass of water >> which will increase the pressure somewhat over ambient. This raises the >> steam formation temp so that the steam over the ambient steam formation >> temp. >> >>> >> >>
