Hi,
On 7-10-2011 1:03, Alan J Fletcher wrote:
At 03:26 PM 10/6/2011, Terry Blanton wrote:
On Thu, Oct 6, 2011 at 5:54 PM, Alan J Fletcher <a...@well.com> wrote:
> The fatcat produced 12,500 kJ
50.4 MJ
I calculated 12,500 kJ in one hour (copy of excel cells -- so excuse
the formatting)
temp 5 A
cu m/hr 0.6
m3 to kg 1000
kg/hr 600 B
kJ/kG 4.187 C
kJ in 1 hr 12561 A*B*C
kJ to kWh 0.000278
kWh 3.491958
kJ 12561
Mouse kJ/day 50
Mouse kJ/hr 2.083333
Mice 6029.28
Let's elaborate a bit more about the eCat that "digested" the eMice.
Found on German wikipedia at http://de.wikipedia.org/wiki/Mäuse it says:
Mäuse erreichen eine Kopf-Rumpf-Länge von 4,5 bis 12,5 Zentimetern,
hinzu kommt ein 3 bis 11 Zentimeter langer Schwanz. Das Gewicht, soweit
bekannt, liegt zwischen 12 und 35 Gramm.
or in English:
Mice reach a head-body-length ranging between 4.5 upto 12.5 cm, added is
a 3 upto 11 cm long tail. The weight, sofar known, is between 12 and 35
grams.
Lets assume an average length of 8.5 cm with a 7 cm long tail and a
diameter of 3 cm and an average weight of 23.5 gram.
Ok now try to squeeze these mice in the smallest possible space and
assume the tails can be placed between the mice requiring no extra space
in the volume in a L*B*H box.
This results in (10 * 8.5 cm) * (30 x 3 cm) * (20 x 3 cm) + (1 * 8.5 cm)
*(1 * 3 cm) * (30 * 3 cm ) , this means these 6030 mice (Hey, we don't
like partial mice ;-) )need a volume of approx. 461 liter and have a
weight of 142 kg.
So I guess we can rule that one out as possible energy source, can't we
? ;-)
Kind regards,
MoB
