A thought occurred to me after the brief discussion that was conducted about the subject of D + D fusion. The wikipedia article on fusion of this type suggests that there is always either a neutron or proton emitted from the reaction when hot fusion takes place. This of course makes sense from the conservation of momentum and energy perspective as Dr. Storms has pointed out.
I commented that a measurement of the actual energy released to the alpha particles of cold fusion reactions would allow someone to calculate the energy and momentum that had to be left behind for the numbers to make sense. My first thoughts on the matter were that this was going to require a large reactionary force if conservation of momentum was to be maintained. I did not actually calculate the magnitude of the momentum or the energy associated with that mass conversion. My choice of a central location from which to observe the reaction made it clear that the alpha particle would be frozen in place pending the release of this mass. With this in mind I think that it would be wise for us to give very serious consideration to the prospect that direct fusion of D + D is unlikely. It would be a good idea to explore different paths that ultimately lead to the release of one or more alpha particles. Of course the source for the reaction must be deuterium. I am confident that this suggestion has been covered before and I am curious about the possible paths that are available. Do any of these fit into place when a review of the active cold fusion metals is considered? Would the addition of a deuterium nuclei be encouraged by Pd for example? Dave -----Original Message----- From: Axil Axil <janap...@gmail.com> To: vortex-l <vortex-l@eskimo.com> Sent: Fri, Jan 25, 2013 9:18 pm Subject: Re: [Vo]:Chemonuclear Transitions Energy can be transferred from one molecule to another threw a quantum mechanical mechanism. Yes http://lightyears.blogs.cnn.com/2011/12/07/diamonds-entangled-in-physics-feat/ In the case of Walmsley's study, photons were showing up in two spots at the same time and causing vibrations within a pair of diamonds. The researchers made it happen by placing two diamonds about 15 centimeters (about 6 inches) apart on a table and then shooting a series of photons at a device called a beam splitter. Most of them went toward one diamond or the other, but a few of the photons went both ways at the same time. When those multitasking photons struck the pair of diamonds, they caused vibrations called phonons with each of the crystals. The light from each of the beams recombines after exiting the crystals. And sometimes when the light is leaving the crystals, it has less energy than when it entered. That's how the researchers could tell that the photon had caused some vibrations. "We know that one diamond is vibrating, but we don't know which one," Walmsley said. "In fact, the universe doesn't know which diamond is vibrating – the diamonds are entangled, with one vibration shared between them, even though they are separated in space." Cheers: Axil On Fri, Jan 25, 2013 at 6:10 PM, Edmund Storms <stor...@ix.netcom.com> wrote: On Jan 25, 2013, at 3:49 PM, <torulf.gr...@bredband.net> <torulf.gr...@bredband.net> wrote: Excuse my grammar. English is not my native language. I will try to answer your questions as simply as possible. Can energy and momentum be transferred from the new He4 to another nucleus at some distains? No Energy can be transferred from one molecule to another threw a quantum mechanical mechanism. Yes, at chemical levels of energy This occurs in photo synthesis there excitations can jump between electrons in different molecules. Yes >From an older tread. http://www.mail-archive.com/vortex-l@eskimo.com/msg75294.html Maybe a similar phenomenon can occur between nucleus? This means the excitation from a He4 and momentum can be transferred The amount energy generated by a nuclear reaction requires direct emission of a particle, which can include a photon. This is observed fact. The magnitude is too great to use mechanisms available in a chemical structure. That is why most nuclear reactions are almost totally independent of the chemical environment. to one or more receiver nucleus. These receiver nucleus must be a special nuclide suitable for receive the energy and have a mechanism to get rid of it. If several nucleus can get energy from one He4 it may radiate it as UV. If this not is possible I suggest that the receiver nucleus is a C12 how decay to 3 He4 as an reversed triple alpha. In absence of receiver nucleus there will be no reactions. But this did not explain the overcome of the coulomb barrier and why its not works in absence of receiver nucleus. I have heard that the conservation of momentum in LENR is commonly explained to "something" how would be like the Mössbauer effect. But I understand this not so easily to explain more exactly. The Mossbauer effect involves a very small energy change. It works only because the target nucleus is very sensitive to the energy of the bombarding gamma. Therefore, the slight effect produced by the chemical lattice become visible. This effect is too small to influence energy being emitted by a fusion reaction in any meaningful way. Ed TG
