In reply to Edmund Storms's message of Thu, 14 Mar 2013 16:31:19 -0600: Hi Ed, [snip] >Jones, I assume you accept that E=mc2 and that if the mass of a >reaction changes, the energy has to come from somewhere. >Here is the mass change > >D = >2.014101778 >H= >1.00727647 >n= >1.0086649 > >The gain in mass is D-n= p >-0.001839592 > which = >1.713569649 > MeV has to be added to provide the increased mass of the resulting p.
You have used the mass of a bare proton and neutron, but the atomic mass of D (i.e. including the electron). The actual reaction energy is therefore .511 MeV larger, (since really only a D nucleus is produced, not atomic D), i.e. 1.7 + 0.5 = 2.2 MeV. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
