I wrote:

Eric, you need to consider some basic requirements. If an energetic
> particle is produced, such as an alpha, a second particle must be present
> to carry away the momentum.
>

Yes -- we are in agreement here.  There are various ways to accomplish this
apart from the Hydroton.  There is an f/H tunneling into a deuteron, for
example, where an electron is expelled instead of a gamma (if I have
understood Robin).  And there is Ron Maimon's approach, where a heavy
nuclide in the vicinity of the reaction shares in the momentum of the
reaction.  I fear we are repeating ourselves now.


> In addition, an upper limit exists to hte energy of an alpha, calculated
> by Peter, above which the alpha would produce detectable secondary
> radiation.
>

Yes -- there are Peter Hagelstein's calculations.  Is there anyone else who
has looked into this, or is the weight of the conclusion about the
detectable secondary radiation resting on Hagelstein's calculations alone?

The various theories all try to find a way for this energy-momentum to be
> lost gradually in the form of photons or phonons that are too weak to be
> detected.  Such a process, once started, must drain all the mass-energy out
> of the He.  This is not just my opinion, but the opinion of everyone who
> has studied the process.
>

Please correct me if I'm wrong, but I don't think Hagelstein's approach
involves a slow release -- I think the quantum is released all at once,
but across countless lattice atoms via phonons, a process that has the
effect of subdividing it up into something harmless.  There's no "leaking"
in that case.  It's a fast reaction, it just isn't concentrated in a single
place.  It's quite possible that I am mistaken in this understanding.

Eric

Reply via email to