I thought he might have done a typo, and mean 10 kWh/h so I emailed him to ask.
He confirmed that it was a typo, and he meant 10kWh/h for the ecat, just like it has always been. If that is the case: 0.91 * 35% of the time = 0.3185 kWh/h *10* * 65% of the time = 6.5 kWh/h total output = 6.8185 kWh/h input = 0.9 * 35% of the time = 0.315 kWh/h COP = 21.65 On Tue, May 14, 2013 at 11:25 AM, Alan Fletcher <a...@well.com> wrote: > > If you split the time between activator and ecat as he suggests you > > get slightly different numbers: > > > > 0.91 * 35% of the time = 0.3185 kWh/h > > 1 * 65% of the time = 0.65 kWh/h > > > > > > total output = 0.9685 kWh/h > > input = 0.9 * 35% of the time = 0.315 kWh/h > > > > > > COP = 3.07 > > That's how I did it at first ... then I reread his statement and thought > he was talking about the total. > > Either way, MUCH less than 100-200 -- and less than his usual guaranteed > COP of 6. > > (And I have no idea of the implication of Terry's "The magic ratio that FE > people have sought!" ) > > -- Patrick www.tRacePerfect.com The daily puzzle everyone can finish but not everyone can perfect! The quickest puzzle ever!
