If it were endothermic, it would never happen.
On Fri, Mar 28, 2014 at 6:32 PM, Daniel Rocha <danieldi...@gmail.com> wrote: > That's not quite correct, you should do like this > > D -> P + N -> 2P + e > > It's endothermic > > > 2014-03-28 16:57 GMT-03:00 Axil Axil <janap...@gmail.com>: > > A neutron becomes a proton with a gain of .75 MeV, >> >> P + N = 2P >> >> >> On Fri, Mar 28, 2014 at 3:21 PM, Daniel Rocha <danieldi...@gmail.com>wrote: >> >>> What neutron decay? Weren't you talking about deuteron yielding 2 >>> hydrogen? >>> >>> >>> 2014-03-28 15:37 GMT-03:00 Axil Axil <janap...@gmail.com>: >>> >>> Jones Beene said: >>>> >>>> "Neutron decay is exothermic, but the stripping reaction itself - where >>>> the neutron is separated from deuterium involves kinetic energy depletion - >>>> so yes, the net reaction is not necessarily gainful unless the kinetic >>>> energy of the deuteron is supplied in a gainful way, or unless the bond >>>> energy is depleted - such as in the nanocavity using a mechanism related to >>>> Casimir - cavity QM or spin coupling." >>>> >>>> >>>> >>>> The energy of magnetic field production is derived from the uncertainty >>>> principle in a optical cavity were the SPPs gathered are compressed. This >>>> mechanism is lossless. >>>> >>>> >>>> >>>> The gain comes from neutron decay. >>>> >>>> >>>> >>>> >>>> >>>> >>>> >>>> On Fri, Mar 28, 2014 at 2:29 PM, Daniel Rocha <danieldi...@gmail.com>wrote: >>>> >>>>> That's an endothermic reaction. And I don't see where it would fit >>>>> anywhere in any scheme. >>>>> >>>>> >>>>> >>>>> -- >>>>> Daniel Rocha - RJ >>>>> danieldi...@gmail.com >>>>> >>>> >>>> >>> >>> >>> -- >>> Daniel Rocha - RJ >>> danieldi...@gmail.com >>> >> >> > > > -- > Daniel Rocha - RJ > danieldi...@gmail.com >