I apologize for responding so tardily. But I have been in transit and outfitting for my summer/fall in Alaska.
Jones-- The dimensions of the emitter associated with spin transitions in a nucleus or during nuclear magnetic momentum transitions does not have anything to do with the size of the nucleus. As robin points out the size of the wave length of the EM radiation does not depend upon the size of the emitting entity. I think it depends upon the differential energy between quantum states involved in the transition to a lower state. The geometry of course is involved in determination of the allowed states, but a typical dimension may not be apparent. That being said I think the halo concept is instructive in thinking about how energy states may change as a virtual particle changes to a stable ground state. I like to think of a virtual di-deuterium particle collapsing to a He particle in the Pd / Deuterium system. In fact the Cooper paring of two Deuterium atoms to form an excited virtual pair, starting out with antiparallel alignment each with high spin quantum number totaling a net of 0 of the target He ground state, may explain the energy fractionation that apparently occurs in small energy increments. Separately, I tend to agree with Robin that the need to try to combine the electric and gravitation forces is not warranted unless it is a consideration in a strong magnetic field to cause the paring to start. This may be more important in the Ni H system where a catalyst is needed--a Cooper pair of electrons or a di-proton. Of course a Pd system may also experience high magnetic fields and assistance in Cooper pairing. I am not sure that the restriction to one dimension in the strong magnetic field involves controlling the gravitational field as well. Bob From: Jones Beene Sent: Sunday, May 18, 2014 3:58 PM To: vortex-l@eskimo.com -----Original Message----- From: mix...@bigpond.com > Why invoke electrogravity when the normal nuclear force will do just fine? Note that the neutrons in the deuterons are already within range of this force, as the deuteron is already bound. Yes, of course. That's the basic problem. The nucleus does not emit in the range which we need to match experimental results (or lack thereof). The problem with "normal" nuclear radiation is that it is very short wavelength - which is not seen in LENR experiments. Working backwards from a spectrum which could have escaped detection, we can hypothesize that there needs to be an emitter geometry which is large enough to emit EUV or x-rays and at the same time, to delay actual fusion until enough energy has been dumped. That requirement eliminates any normal nucleus. This gets into antenna theory. How can a femtometer particle emit ultraviolet? Typically it cannot as the geometry is way too disproportionate. Possibly a halo nucleus can do this, or maybe the halo is too small as well. If that is the case, then the rationalization (of any kind of stepwise release) is dead.
