Thanx, it was as you pointed out. But how can I correctly use the modal
window. It's working but the code is quiet dirty.
On Nov 15, 2012 9:03 PM, "Richard Vézina" <ml.richard.vez...@gmail.com>
wrote:
> I am not pretty experienced with SQLFORM.grid, but the way you use
> bootstrap modal seems wrong...
>
> About the id problem, I notice that one time use row.id and the other
> row.office.id maybe your problem come from there?!
>
> Richard
>
> On Thu, Nov 15, 2012 at 12:58 AM, Teddy Nyambe <software....@gmail.com>wrote:
>
>> Hi,
>>
>> I have the following action in the controller, doing a join to display
>> "office name" and a reference to department of "department name" to
>> which office belongs...but i have an error in the link since I have a
>> modal window am opening to edit/add/delete details...this is the
>> error:
>>
>> <type 'exceptions.AttributeError'> 'Row' object has no attribute 'id'
>>
>>
>> def office():
>> db.office.id.readable = False
>> query = ((db.office.department == db.department.id))
>> #((db.contact.date_of_birth < “1990-11-18”))
>> fields = (db.office.name, db.department.name)
>> link = [lambda row: A('Edit', _class='btn', _role='button',
>> _onclick='dept_edit('+str(row.office.id)+');',**{'_data-toggle':'modal'})
>> ,lambda row: A('Delete', _class='btn', _role='button',
>> _onclick='dept_delete('+str(row.id)+');',**{'_data-toggle':'modal'})]
>> headers = {'db.office.name': 'Office Name','db.department.name':
>> 'Department'}
>> default_sort_order=[db.office.name]
>>
>> form = SQLFORM.grid(query=query, headers=headers,
>> orderby=default_sort_order ,links=link, create=False, deletable=True,
>> editable=False, maxtextlength=64, paginate=25)
>> return dict(form=form)
>>
>> How do I pass an id of a row in lambda for the link parameter of the
>> SQLFORM.grid.
>>
>> Been stuck with this error for a day now!!
>>
>> Kind regards,
>>
>> Teddy L.
>>
>> --
>>
>>
>>
>>
> --
>
>
>
>
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