Ouch, I'm going to have to defer to to someone who understands smartgrid better than I do. You've got me stumped on this one.
On Fri, Feb 22, 2013 at 2:48 PM, Alex Glaros <alexgla...@gmail.com> wrote: > thanks for offering to take a look. > > Screen shots here: > https://docs.google.com/document/d/1e517YRN8FK08vqsVWmp1UuZ0LLevCNlkrhWyCkBQ7uQ/edit?usp=sharing > > Alex > > > On Friday, February 22, 2013 12:16:39 PM UTC-8, Jim S wrote: > >> Sorry, I'm kinda lost in what you're trying to do. Can you show it in >> code or screen shots? >> >> -Jim >> >> >> On Fri, Feb 22, 2013 at 12:08 PM, Alex Glaros <alexg...@gmail.com> wrote: >> >>> There is a grandparent (HumanLanguage), parent (DictionaryType), child >>> (Word), relationship. If I go straight from the grandparent to the child, >>> "represent" works. >>> (First I click on HumanLangages, then I click on Word) >>> >>> If I go from the parent to the child, I get this message: <type >>> 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1 given) >>> (First I click on HumanLangages, then I click on DictionaryType, then, I >>> click on Word) >>> >>> If I reduce the number of parms to db.Word.dictionaryTypeID.**represent >>> = lambda id: db.DictionaryType(id).**dictionaryName, then it works if I >>> go from the parent to the child, but if I go from the grandparent to the >>> child, I get <type 'exceptions.TypeError'> <lambda>() takes exactly 1 >>> argument (2 given). >>> >>> If a join was allowed, it would solve the problem but I think they are >>> not supported in smartgrid. >>> >>> Any ideas would be much appreciated, >>> >>> Thanks, >>> >>> Alex >>> >>> >>> On Friday, February 22, 2013 5:24:48 AM UTC-8, Jim S wrote: >>> >>>> Depends on whether or not you want that behavior globally or not. >>>> Remember, your model gets executed on every request. So, if you want that >>>> behavior globally I'd put it there. If you just need it for one instance, >>>> put it in the controller. >>>> >>>> -Jim >>>> >>>> >>>> On Fri, Feb 22, 2013 at 12:20 AM, Alex Glaros <alexg...@gmail.com>wrote: >>>> >>>>> It worked Jim >>>>> >>>>> thanks so much for going through the process of writing and testing >>>>> the code. >>>>> >>>>> I'm new to web2py, is there any preference as to where that statement >>>>> goes: controller or model? >>>>> >>>>> much appreciated, >>>>> >>>>> Alex >>>>> >>>>> >>>>> On Thu, Feb 21, 2013 at 8:31 PM, Jim S <j...@qlf.com> wrote: >>>>> >>>>>> Add this line before creating your smartgrid: >>>>>> >>>>>> db.Word.dictionaryTypeID.**repre**sent = lambda s,r: s.dictionaryName >>>>>> >>>>>> Does that help? It worked for the trimmed down model I made... >>>>>> >>>>>> -Jim >>>>>> >>>>>> >>>>>> On Thursday, February 21, 2013 9:16:39 PM UTC-6, Alex Glaros wrote: >>>>>>> >>>>>>> db.define_table('**HumanLanguage**',Field('**languageName','** >>>>>>> string'),Field(**'**forumLocations','string'),**Fiel**d('comments','string'), >>>>>>> auth.signature) >>>>>>> db.HumanLanguage.languageName.****requires = IS_NOT_EMPTY() >>>>>>> >>>>>>> db.define_table('Word',Field('****wordName','string'), Field >>>>>>> ('definition', 'string'), Field('languageID','reference >>>>>>> HumanLanguage'),Field('**diction**aryTypeID','reference >>>>>>> DictionaryType'),Field('**wordRe**ferenceModelID','**reference >>>>>>> WordReferenceModel'), Field('comments','string'), auth.signature) >>>>>>> db.Word.languageID.requires = IS_IN_DB(db, 'HumanLanguage.id', >>>>>>> '%(languageName)s',zero=T('**cho**ose one')) >>>>>>> db.Word.dictionaryTypeID.**requi**res = IS_IN_DB(db, >>>>>>> 'DictionaryType.id', '%(dictionaryName)s',zero=T('**c**hoose one')) >>>>>>> db.Word.wordName.requires = IS_NOT_EMPTY() >>>>>>> db.Word.wordReferenceModelID.**r**equires = IS_NULL_OR(IS_IN_DB(db, >>>>>>> 'WordReferenceModel.id', '%(wordID)s',zero=T('choose one'))) >>>>>>> >>>>>>> ## Uses English language as standard connector between all >>>>>>> languages. WordID below points to the English version of the word that >>>>>>> is >>>>>>> the standard. The reason "Is_Null" clause is there is because the first >>>>>>> time the word is encountered, it won't be in the English dictionary >>>>>>> db.define_table('**WordReference**Model',Field('**wordID','**reference >>>>>>> Word'),Field('**dictionaryTypeID**','reference DictionaryType'), >>>>>>> Field('picture', 'upload', default=''),Field('comments','****string'), >>>>>>> auth.signature) >>>>>>> db.WordReferenceModel.wordID.**r**equires = IS_NOT_EMPTY() >>>>>>> db.WordReferenceModel.wordID.**r**equires = IS_IN_DB(db, 'Word.id', >>>>>>> '%(wordName)s',zero=T('choose one')) >>>>>>> db.WordReferenceModel.**dictiona**ryTypeID.requires = IS_IN_DB(db, >>>>>>> 'DictionaryType.id', '%(dictionaryName)s',zero=T('**c**hoose one')) >>>>>>> ## dictionary_type_query = (db.DictionaryType.**dictionaryN** >>>>>>> ame=='English') >>>>>>> ## /* need this too for wordReferenceModel */ >>>>>>> >>>>>>> ## Dictionary type means what category of dictionary is it? Medical, >>>>>>> computer,etc. There is one for each language. >>>>>>> db.define_table('**DictionaryTyp**e',Field('**dictionaryName','** >>>>>>> string'),**Field('comments','**string'), >>>>>>> Field('languageID','reference HumanLanguage'), >>>>>>> Field('**DictionaryReferenceMode**lID', 'reference >>>>>>> DictionaryReferenceModel'), auth.signature) >>>>>>> db.DictionaryType.**dictionaryNa**me.requires = IS_NOT_EMPTY() >>>>>>> db.DictionaryType.languageID.**r**equires = IS_IN_DB(db, >>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('**cho**ose one')) >>>>>>> db.DictionaryType.**DictionaryRe**ferenceModelID.**requires = >>>>>>> IS_IN_DB(db, 'DictionaryReferenceModel.id', >>>>>>> '%(DictionaryTypeID)s',zero=T( >>>>>>> ****'choose one')) >>>>>>> >>>>>>> ## Uses English dictionary type as standard connector between all >>>>>>> dictionary types. DictionaryType.id points to the English >>>>>>> DictionaryType.id >>>>>>> db.define_table('**DictionaryRef**erenceModel', >>>>>>> Field('DictionaryTypeID','**refe**rence DictionaryType'),Field('** >>>>>>> commen**ts','string'), >>>>>>> auth.signature) >>>>>>> db.DictionaryReferenceModel.**Di**ctionaryTypeID.requires = >>>>>>> IS_NOT_EMPTY() >>>>>>> >>>>>>> db.define_table('Synonyms',**Fie**ld('synonymName','string'),**Fie**ld('wordID','reference >>>>>>> Word'),Field('comments','**strin**g'), >>>>>>> auth.signature) >>>>>>> db.Synonyms.synonymName.**requir**es = IS_NOT_EMPTY() >>>>>>> db.Synonyms.wordID.requires = IS_NOT_EMPTY() >>>>>>> db.Synonyms.wordID.requires = IS_IN_DB(db, 'Word.id', >>>>>>> '%(Word)s',zero=T('choose one')) >>>>>>> >>>>>>> db.define_table('**PublicComment**s',Field('wordID'**,'reference >>>>>>> Word'),Field('comments','**strin**g'), >>>>>>> auth.signature) >>>>>>> db.PublicComments.comments.**req**uires = IS_NOT_EMPTY() >>>>>>> db.PublicComments.wordID.**requi**res = IS_NOT_EMPTY() >>>>>>> db.PublicComments.wordID.**requi**res = IS_IN_DB(db, 'Word.id', >>>>>>> '%(wordName)s',zero=T('choose one')) >>>>>>> >>>>>>> >>>>>>> On Thursday, February 21, 2013 6:10:56 PM UTC-8, Jim S wrote: >>>>>>>> >>>>>>>> Can you show the model code? >>>>>>>> >>>>>>>> -Jim >>>>>>>> >>>>>>>> On Thursday, February 21, 2013 7:35:52 PM UTC-6, Alex Glaros wrote: >>>>>>>>> >>>>>>>>> Instead of *db.Word.dictionaryTypeID* displaying (which is a >>>>>>>>> foreign key in db.Word), I’d like a value from the foreign table to >>>>>>>>> appear, >>>>>>>>> i.e., DictionaryType. dictionaryName. >>>>>>>>> >>>>>>>>> >>>>>>>>> In the example below, when user cascades down to the Word table, >>>>>>>>> it only shows db.Word.dictionaryTypeID but I’d like to add the >>>>>>>>> corresponding DictionaryType. dictionaryName value to it. >>>>>>>>> >>>>>>>>> >>>>>>>>> def search_lang(): >>>>>>>>> >>>>>>>>> grid = SQLFORM.smartgrid(db.**HumanLang**uage, >>>>>>>>> linked_tables=['Word','**Diction**aryType'], fields = [ >>>>>>>>> db.HumanLanguage.id, db.HumanLanguage.languageName, db.Word.id, >>>>>>>>> db.Word.wordName, db.Word.definition, db.DictionaryType.** >>>>>>>>> dictionaryNa**me, >>>>>>>>> >>>>>>>>> *db.Word.dictionaryTypeID*], >>>>>>>>> >>>>>>>>> user_signature=False) >>>>>>>>> >>>>>>>>> return dict(grid=grid) >>>>>>>>> >>>>>>>>> >>>>>>>>> id<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.id> >>>>>>>>> >>>>>>>>> Wordname<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.wordName> >>>>>>>>> >>>>>>>>> Definition<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.definition> >>>>>>>>> >>>>>>>>> Dictionarytypeid<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.dictionaryTypeID> >>>>>>>>> 1 beaker glass jar 1 >>>>>>>>> >>>>>>>>> >>>>>>>>> Want to replace the "1" under Dictionarytypeid with value from >>>>>>>>> foreign table. >>>>>>>>> >>>>>>>>> Thanks, >>>>>>>>> >>>>>>>>> Alex Glaros >>>>>>>>> >>>>>>>> -- >>>>>> >>>>>> --- >>>>>> You received this message because you are subscribed to the Google >>>>>> Groups "web2py-users" group. >>>>>> To unsubscribe from this group and stop receiving emails from it, >>>>>> send an email to web2py+un...@**googlegroups.com. >>>>>> >>>>>> For more options, visit >>>>>> https://groups.google.com/**grou**ps/opt_out<https://groups.google.com/groups/opt_out> >>>>>> . >>>>>> >>>>>> >>>>>> >>>>> >>>>> -- >>>>> >>>>> --- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "web2py-users" group. >>>>> To unsubscribe from this group and stop receiving emails from it, send >>>>> an email to web2py+un...@**googlegroups.com. >>>>> >>>>> For more options, visit >>>>> https://groups.google.com/**grou**ps/opt_out<https://groups.google.com/groups/opt_out> >>>>> . >>>>> >>>>> >>>>> >>>> >>>> -- >>> >>> --- >>> You received this message because you are subscribed to the Google >>> Groups "web2py-users" group. >>> To unsubscribe from this group and stop receiving emails from it, send >>> an email to web2py+un...@**googlegroups.com. >>> For more options, visit >>> https://groups.google.com/**groups/opt_out<https://groups.google.com/groups/opt_out> >>> . >>> >>> >>> >> >> -- > > --- > You received this message because you are subscribed to the Google Groups > "web2py-users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to web2py+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/groups/opt_out. > > > -- --- You received this message because you are subscribed to the Google Groups "web2py-users" group. 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