Does it occur after the definition of db.DictionaryType in your model file?
Sorry for the dumb questions, just going over mistakes I've made in the
past...
-Jim
On Sat, Feb 23, 2013 at 2:09 PM, Alex Glaros <alexgla...@gmail.com> wrote:
> db.define_table('Word',
> Field('wordName','string'),
> Field ('definition', 'string'),
> Field('languageID','reference HumanLanguage'),
> Field('dictionaryTypeID',*db.DictionaryType*),
> Field('wordReferenceModelID','reference WordReferenceModel'),
> Field('comments','string'), auth.signature)
>
> On Sat, Feb 23, 2013 at 12:01 PM, Jim Steil <ato.st...@gmail.com> wrote:
>
>>
>> Can you paste the table definition that choked on you?
>>
>> -Jim
>>
>>
>> On Sat, Feb 23, 2013 at 1:34 PM, Alex Glaros <alexgla...@gmail.com>wrote:
>>
>>> web2py doesn't seem to accept that format on my windows version. I get
>>>
>>> <type 'exceptions.AttributeError'> 'DAL' object has no attribute
>>> 'DictionaryType'
>>> The error below doesn't come up when there is no data:
>>>
>>> *<type 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1
>>> given)*
>>>
>>> The represent attribute works if there are two files in play instead of
>>> three
>>>
>>> I created a simplified version and changed every field name in case
>>> there was some reserved word problem but it didn't work
>>>
>>> What I will do is write something similar from scratch with different
>>> table and field names.
>>>
>>> Thanks,
>>>
>>> Alex
>>>
>>> On Sat, Feb 23, 2013 at 8:35 AM, Jim S <j...@qlf.com> wrote:
>>>
>>>> Just to be clear, he isn't asking just to remove quotes, but to specify
>>>> your reference columns as:
>>>>
>>>> db.table_name
>>>>
>>>> instead of
>>>>
>>>> 'reference table_name'
>>>>
>>>> -Jim
>>>>
>>>> On Friday, February 22, 2013 7:14:18 PM UTC-6, Alex Glaros wrote:
>>>>
>>>>> thanks for giving it a shot but depending upon whether I use quotes or
>>>>> not, either the data column disappears from the web page or I get errors
>>>>>
>>>>> On Fri, Feb 22, 2013 at 1:47 PM, Kyle Flanagan <kylefl...@gmail.com>wrote:
>>>>>
>>>>>> Have you tried adding a format to your tables and defining your
>>>>>> tables using objects instead of 'reference...'?
>>>>>>
>>>>>> I'm no web2py expert by any means, but I had a similar situation and
>>>>>> when I changed the reference for my foreign id to db.other_table instead
>>>>>> of
>>>>>> 'reference other_table,' the format defined for that table was used
>>>>>> instead
>>>>>> of the id.
>>>>>>
>>>>>> Something like this:
>>>>>> db.define_table('HumanLanguage',
>>>>>> Field('languageName','string'),
>>>>>> Field('forumLocations','string'),
>>>>>>
>>>>>> Field('comments','string'),
>>>>>>
>>>>>> format = '%(languageName)s'), # define a format
>>>>>> auth.signature)
>>>>>> db.HumanLanguage.languageName.requires = IS_NOT_EMPTY()
>>>>>>
>>>>>> ##
>>>>>> ## Define DictionaryReferenceModel and WordReferenceModel above here
>>>>>> ## DictionaryReferenceModel, WordReferenceModel should have a format
>>>>>> ##
>>>>>>
>>>>>>
>>>>>> ## Dictionary type means what category of dictionary is it? Medical,
>>>>>> computer,etc. There is one for each language.
>>>>>> db.define_table('DictionaryType',
>>>>>>
>>>>>> Field('dictionaryName','string'),
>>>>>>
>>>>>> Field('comments','string'),
>>>>>>
>>>>>> Field('languageID',db.HumanLanguage ), # changed to object
>>>>>> Field('DictionaryReferenceModelID', db.DictionaryReferenceModel), #
>>>>>> changed to object
>>>>>> format = '%(dictionaryName)s', # define format
>>>>>>
>>>>>> auth.signature)
>>>>>> db.DictionaryType.dictionaryName.requires = IS_NOT_EMPTY()
>>>>>> db.DictionaryType.languageID.requires = IS_IN_DB(db,
>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('choose one'))
>>>>>> db.DictionaryType.DictionaryReferenceModelID.requires = IS_IN_DB(db,
>>>>>> 'DictionaryReferenceModel.id', '%(DictionaryTypeID)s',zero=T('choose
>>>>>> one'))
>>>>>>
>>>>>>
>>>>>> db.define_table('Word',
>>>>>>
>>>>>> Field('wordName','string'),
>>>>>> Field ('definition','string'),
>>>>>> Field('languageID', db.HumanLanguage ), # changed to object
>>>>>> Field('dictionaryTypeID',db.DictionaryType), # changed to object
>>>>>> Field('wordReferenceModelID',db.WordReferenceModel), # changed to
>>>>>> object
>>>>>>
>>>>>> Field('comments','string'),
>>>>>> auth.signature)
>>>>>> db.Word.languageID.requires = IS_IN_DB(db, 'HumanLanguage.id',
>>>>>> '%(languageName)s',zero=T('choose one'))
>>>>>> db.Word.dictionaryTypeID.requires = IS_IN_DB(db, 'DictionaryType.id',
>>>>>> '%(dictionaryName)s',zero=T('choose one'))
>>>>>> db.Word.wordName.requires = IS_NOT_EMPTY()
>>>>>> db.Word.wordReferenceModelID.requires = IS_NULL_OR(IS_IN_DB(db,
>>>>>> 'WordReferenceModel.id', '%(wordID)s',zero=T('choose one')))
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> On Friday, February 22, 2013 2:48:19 PM UTC-6, Alex Glaros wrote:
>>>>>>>
>>>>>>> thanks for offering to take a look.
>>>>>>>
>>>>>>> Screen shots here:
>>>>>>> https://docs.google.com/document/d/1e517YRN8FK08vqsVWmp1UuZ0LLevCNlkrhWyCkBQ7uQ/edit?usp=sharing
>>>>>>>
>>>>>>> Alex
>>>>>>>
>>>>>>> On Friday, February 22, 2013 12:16:39 PM UTC-8, Jim S wrote:
>>>>>>>>
>>>>>>>> Sorry, I'm kinda lost in what you're trying to do. Can you show it
>>>>>>>> in code or screen shots?
>>>>>>>>
>>>>>>>> -Jim
>>>>>>>>
>>>>>>>>
>>>>>>>> On Fri, Feb 22, 2013 at 12:08 PM, Alex Glaros
>>>>>>>> <alexg...@gmail.com>wrote:
>>>>>>>>
>>>>>>>>> There is a grandparent (HumanLanguage), parent (DictionaryType),
>>>>>>>>> child (Word), relationship. If I go straight from the grandparent to
>>>>>>>>> the
>>>>>>>>> child, "represent" works.
>>>>>>>>> (First I click on HumanLangages, then I click on Word)
>>>>>>>>>
>>>>>>>>> If I go from the parent to the child, I get this message: <type
>>>>>>>>> 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1 given)
>>>>>>>>> (First I click on HumanLangages, then I click on DictionaryType,
>>>>>>>>> then, I click on Word)
>>>>>>>>>
>>>>>>>>> If I reduce the number of parms
>>>>>>>>> to db.Word.dictionaryTypeID.represent = lambda id:
>>>>>>>>> db.DictionaryType(id).dictionaryName, then it works if I go from the
>>>>>>>>> parent
>>>>>>>>> to the child, but if I go from the grandparent to the child, I get
>>>>>>>>> <type
>>>>>>>>> 'exceptions.TypeError'> <lambda>() takes exactly 1 argument (2 given).
>>>>>>>>>
>>>>>>>>> If a join was allowed, it would solve the problem but I think they
>>>>>>>>> are not supported in smartgrid.
>>>>>>>>>
>>>>>>>>> Any ideas would be much appreciated,
>>>>>>>>>
>>>>>>>>> Thanks,
>>>>>>>>>
>>>>>>>>> Alex
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On Friday, February 22, 2013 5:24:48 AM UTC-8, Jim S wrote:
>>>>>>>>>
>>>>>>>>>> Depends on whether or not you want that behavior globally or not.
>>>>>>>>>> Remember, your model gets executed on every request. So, if you
>>>>>>>>>> want that
>>>>>>>>>> behavior globally I'd put it there. If you just need it for one
>>>>>>>>>> instance,
>>>>>>>>>> put it in the controller.
>>>>>>>>>>
>>>>>>>>>> -Jim
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> On Fri, Feb 22, 2013 at 12:20 AM, Alex Glaros <alexg...@gmail.com
>>>>>>>>>> > wrote:
>>>>>>>>>>
>>>>>>>>>>> It worked Jim
>>>>>>>>>>>
>>>>>>>>>>> thanks so much for going through the process of writing and
>>>>>>>>>>> testing the code.
>>>>>>>>>>>
>>>>>>>>>>> I'm new to web2py, is there any preference as to where that
>>>>>>>>>>> statement goes: controller or model?
>>>>>>>>>>>
>>>>>>>>>>> much appreciated,
>>>>>>>>>>>
>>>>>>>>>>> Alex
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> On Thu, Feb 21, 2013 at 8:31 PM, Jim S <j...@qlf.com> wrote:
>>>>>>>>>>>
>>>>>>>>>>>> Add this line before creating your smartgrid:
>>>>>>>>>>>>
>>>>>>>>>>>> db.Word.dictionaryTypeID.represent = lambda s,r:
>>>>>>>>>>>> s.dictionaryName
>>>>>>>>>>>>
>>>>>>>>>>>> Does that help? It worked for the trimmed down model I made...
>>>>>>>>>>>>
>>>>>>>>>>>> -Jim
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> On Thursday, February 21, 2013 9:16:39 PM UTC-6, Alex Glaros
>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>
>>>>>>>>>>>>> db.define_table('HumanLanguage',Field('languageName','string'),Field('forumLocations','string'),Field('comments','string'),
>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>> db.HumanLanguage.languageName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>
>>>>>>>>>>>>> db.define_table('Word',Field('wordName','string'), Field
>>>>>>>>>>>>> ('definition', 'string'), Field('languageID','reference
>>>>>>>>>>>>> HumanLanguage'),Field('dictionaryTypeID','reference
>>>>>>>>>>>>> DictionaryType'),Field('wordReferenceModelID','reference
>>>>>>>>>>>>> WordReferenceModel'), Field('comments','string'), auth.signature)
>>>>>>>>>>>>> db.Word.languageID.requires = IS_IN_DB(db, 'HumanLanguage.id',
>>>>>>>>>>>>> '%(languageName)s',zero=T('choose one'))
>>>>>>>>>>>>> db.Word.dictionaryTypeID.requires = IS_IN_DB(db,
>>>>>>>>>>>>> 'DictionaryType.id', '%(dictionaryName)s',zero=T('choose one'))
>>>>>>>>>>>>> db.Word.wordName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>> db.Word.wordReferenceModelID.requires =
>>>>>>>>>>>>> IS_NULL_OR(IS_IN_DB(db, 'WordReferenceModel.id',
>>>>>>>>>>>>> '%(wordID)s',zero=T('choose one')))
>>>>>>>>>>>>>
>>>>>>>>>>>>> ## Uses English language as standard connector between all
>>>>>>>>>>>>> languages. WordID below points to the English version of the word
>>>>>>>>>>>>> that is
>>>>>>>>>>>>> the standard. The reason "Is_Null" clause is there is because the
>>>>>>>>>>>>> first
>>>>>>>>>>>>> time the word is encountered, it won't be in the English
>>>>>>>>>>>>> dictionary
>>>>>>>>>>>>> db.define_table('WordReferenceModel',Field('wordID','reference
>>>>>>>>>>>>> Word'),Field('dictionaryTypeID','reference DictionaryType'),
>>>>>>>>>>>>> Field('picture', 'upload', default=''),Field('comments','string'),
>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>> db.WordReferenceModel.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>> db.WordReferenceModel.wordID.requires = IS_IN_DB(db,
>>>>>>>>>>>>> 'Word.id', '%(wordName)s',zero=T('choose one'))
>>>>>>>>>>>>> db.WordReferenceModel.dictionaryTypeID.requires = IS_IN_DB(db,
>>>>>>>>>>>>> 'DictionaryType.id', '%(dictionaryName)s',zero=T('choose one'))
>>>>>>>>>>>>> ## dictionary_type_query =
>>>>>>>>>>>>> (db.DictionaryType.dictionaryName=='English')
>>>>>>>>>>>>> ## /* need this too for wordReferenceModel */
>>>>>>>>>>>>>
>>>>>>>>>>>>> ## Dictionary type means what category of dictionary is it?
>>>>>>>>>>>>> Medical, computer,etc. There is one for each language.
>>>>>>>>>>>>> db.define_table('DictionaryType',Field('dictionaryName','string'),Field('comments','string'),
>>>>>>>>>>>>> Field('languageID','reference HumanLanguage'),
>>>>>>>>>>>>> Field('DictionaryReferenceModelID', 'reference
>>>>>>>>>>>>> DictionaryReferenceModel'), auth.signature)
>>>>>>>>>>>>> db.DictionaryType.dictionaryName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>> db.DictionaryType.languageID.requires = IS_IN_DB(db,
>>>>>>>>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('choose one'))
>>>>>>>>>>>>> db.DictionaryType.DictionaryReferenceModelID.requires =
>>>>>>>>>>>>> IS_IN_DB(db, 'DictionaryReferenceModel.id',
>>>>>>>>>>>>> '%(DictionaryTypeID)s',zero=T('choose one'))
>>>>>>>>>>>>>
>>>>>>>>>>>>> ## Uses English dictionary type as standard connector between
>>>>>>>>>>>>> all dictionary types. DictionaryType.id points to the English
>>>>>>>>>>>>> DictionaryType.id
>>>>>>>>>>>>> db.define_table('DictionaryReferenceModel',
>>>>>>>>>>>>> Field('DictionaryTypeID','reference
>>>>>>>>>>>>> DictionaryType'),Field('comments','string'),
>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>> db.DictionaryReferenceModel.DictionaryTypeID.requires =
>>>>>>>>>>>>> IS_NOT_EMPTY()
>>>>>>>>>>>>>
>>>>>>>>>>>>> db.define_table('Synonyms',Field('synonymName','string'),Field('wordID','reference
>>>>>>>>>>>>> Word'),Field('comments','string'),
>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>> db.Synonyms.synonymName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>> db.Synonyms.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>> db.Synonyms.wordID.requires = IS_IN_DB(db, 'Word.id',
>>>>>>>>>>>>> '%(Word)s',zero=T('choose one'))
>>>>>>>>>>>>>
>>>>>>>>>>>>> db.define_table('PublicComments',Field('wordID','reference
>>>>>>>>>>>>> Word'),Field('comments','string'),
>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>> db.PublicComments.comments.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>> db.PublicComments.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>> db.PublicComments.wordID.requires = IS_IN_DB(db, 'Word.id',
>>>>>>>>>>>>> '%(wordName)s',zero=T('choose one'))
>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> On Thursday, February 21, 2013 6:10:56 PM UTC-8, Jim S wrote:
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> Can you show the model code?
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> -Jim
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> On Thursday, February 21, 2013 7:35:52 PM UTC-6, Alex Glaros
>>>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Instead of *db.Word.dictionaryTypeID* displaying (which is
>>>>>>>>>>>>>>> a foreign key in db.Word), I’d like a value from the foreign
>>>>>>>>>>>>>>> table to
>>>>>>>>>>>>>>> appear, i.e., DictionaryType. dictionaryName.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> In the example below, when user cascades down to the Word
>>>>>>>>>>>>>>> table, it only shows db.Word.dictionaryTypeID but I’d like to
>>>>>>>>>>>>>>> add the
>>>>>>>>>>>>>>> corresponding DictionaryType. dictionaryName value to it.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> def search_lang():
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> grid = SQLFORM.smartgrid(db.HumanLanguage,
>>>>>>>>>>>>>>> linked_tables=['Word','DictionaryType'], fields = [
>>>>>>>>>>>>>>> db.HumanLanguage.id, db.HumanLanguage.languageName,
>>>>>>>>>>>>>>> db.Word.id, db.Word.wordName, db.Word.definition,
>>>>>>>>>>>>>>> db.DictionaryType.dictionaryName,
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> *db.Word.dictionaryTypeID*],
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> user_signature=False)
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> return dict(grid=grid)
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> id<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.id>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Wordname<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.wordName>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Definition<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.definition>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Dictionarytypeid<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.dictionaryTypeID>
>>>>>>>>>>>>>>> 1 beaker glass jar 1
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Want to replace the "1" under Dictionarytypeid with value
>>>>>>>>>>>>>>> from foreign table.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Thanks,
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Alex Glaros
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>> --
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