After disabling the key constraints none of those errors about it have appeared. I am grateful for the assistance and will return it anyway I can. I will post a summary here for anyone attempting this also. Thanks a million!
On Wednesday, January 22, 2014 12:03:26 PM UTC-6, web2pygroup wrote: > > That works great, thank you!!! My only remaining question is that when I > try to edit the first record "main" in the appadmin I get the foreign key > error. I read here -> > https://groups.google.com/forum/#!topic/web2py/klspqXpha4E <- about how > to disable it. Wasn't sure if I should do that or not... The other > records do not act up when changed, just that one so I'm sure I could work > around that but, just in case someone else manages the site... I'm not > sure. Thoughts? > > On Tuesday, January 21, 2014 11:03:46 PM UTC-6, Massimo Di Pierro wrote: >> >> Sorry typo. Let's try again: >> >> db.define_table('store_catalog', >> Field('title'), >> Field('slug',requires=IS_SLUG(),compute=lambda row: >> IS_SLUG.urlify(row.titl\ >> e)), >> Field('parent_id','reference store_catalog')) >> >> id1 = db.store_catalog.insert(title='main') >> id2 = db.store_catalog.insert(title='one',parent_id=id1) >> id3 = db.store_catalog.insert(title='two',parent_id=id2) >> >> def menu_rec(items): return >> [(x.title,None,URL('action',args=x.slug),menu_rec(x\ >> .children)) for x in items or []] >> response.menu = menu_rec(db(db.store_catalog).select().as_trees()) >> print response.menu >> >> On Tuesday, 21 January 2014 12:17:19 UTC-6, web2pygroup wrote: >>> >>> Here's what I've tried so far and here's the results if it helps any to >>> get me on the right track, plus I hope this helps someone else looking for >>> this to because this is something very commonly done in PHP. >>> >>> I have tried changing this: >>> response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]]) >>> >>> to this: >>> response.menu3[-1]+=([(T(subcat.subcategory)), False, 'link',]) >>> >>> Which changes the output in the shell to: >>> [<lazyT 'Catalog'>, >>> False, >>> '', >>> [<lazyT 'Animals'>, >>> False, >>> 'link', >>> <lazyT 'Dogs'>, >>> False, >>> 'link', >>> <lazyT 'Cats'>, >>> False, >>> 'link']] >>> >>> Which obviously isn't correct. >>> >>> Continuing: >>> >>> original: >>> response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]]) >>> >>> to this: >>> response.menu3+=([[(T(subcat.subcategory)), False, 'link',]]) >>> >>> Gives this in the shell output: >>> [<lazyT 'Catalog'>, >>> False, >>> '', >>> [<lazyT 'Animals'>, False, 'link'], >>> [<lazyT 'Dogs'>, False, 'link'], >>> [<lazyT 'Cats'>, False, 'link']] >>> >>> Again obviously incorrect. Continuing: >>> >>> original: >>> response.menu3+=([[(T(subcat.subcategory)), False, 'link',]]) >>> >>> changed: >>> response.menu3[-1]+=((T(subcat.subcategory)), False, 'link',) >>> >>> Shell output shows: >>> [<lazyT 'Catalog'>, >>> False, >>> '', >>> [<lazyT 'Animals'>, >>> False, >>> 'link', >>> <lazyT 'Dogs'>, >>> False, >>> 'link', >>> <lazyT 'Cats'>, >>> False, >>> 'link']] >>> >>> I tried additional variations but, not sure how much space we have here >>> to keep going with my 2 weeks worth of work. Essentially the end result is >>> the same a bracket missing to seperate the subcategories. I've been able >>> to modify and add to lists before, however I've never really experienced a >>> situation where the negative slice appears to be ignored (removing the >>> bracket at the end of dogs and beginning of cats as it is doing for the >>> main category Animals as can be seen), even removed the negative slice >>> ([-1]) for the main categories iteration and when I do it clearly shows >>> that it is actually doing the negative slice properly because the brackets >>> come back at the end of Animals, unlike the subcategories that do not >>> appear to be removing the bracket(s) >>> >>> >>> On Monday, January 20, 2014 2:33:50 PM UTC-6, web2pygroup wrote: >>>> >>>> >>>> Hi all, >>>> >>>> I have been trying for a little over 2 weeks to figure this out... >>>> >>>> I'm trying to generate a menu that drops down, I have been able to >>>> statically create it by overwriting sample app that has the same drop down >>>> menu like the web2py.com site. >>>> >>>> I have this in my db.py: >>>> db.define_table('store_catalog', >>>> Field('maincategory', 'string'), >>>> Field('subcategory', 'string'), >>>> Field('description', 'text')) >>>> >>>> >>>> in my menu.py I have gotten this so far: >>>> response.menu=[] >>>> response.menu.append([T('Catalog'), False, '', >>>> [(T('%s' % menucatchoice['maincategory']), False, 'link', >>>> [(T('%s' % menucatchoice['subcategory']), False, >>>> 'link'),]) for menucatchoice in rows ] ]) >>>> >>>> It gets me a drop down menu except that for each subcategory it repeats >>>> adding it to the main category. Let's say there is only 1 main category >>>> and >>>> 2 subs that go after that >>>> Catalog (this just shows with the caret next to it as intended) >>>> MainCategory >>>> Sub >>>> Sub >>>> What I have does put the "Catalog" for the first but, what I get is: >>>> MainCategory >>>> (blank) >>>> MainCategory(don't want this it's being repeated) >>>> Subcategory >>>> MainCategory(and this one is also a repeat) >>>> Subcategory >>>> >>>> I have tried to break out the response.menu with so many different >>>> .appends it's not funny. I have also tried adding the "[-1]". This was >>>> the closest I have gotten to what I want it to look like. I'm at an >>>> absolute loss on this, any and all help would be greatly appreciated. >>>> >>> -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
