Always use Python to build your paths:
import os
filepath = os.path.join(request.folder, 'view', 'pictures', filename)
Again, don't just use the filename provided by the user, as that is a
security vulnerability.
Anthony
On Wednesday, December 16, 2015 at 10:13:10 AM UTC-5, Adrien wrote:
>
> For the path, i just don't write my path but it works only when i used the
> all path (from C:/ to my folder pictures like
> "C:/Adrien/web2py/applications/myApp/view/pictures/", don't know how to
> write only "pictures/"). So if i can resolve this and find how to change
> the filename, it's good and my problem will be fix.
>
> For SQLFORM.factory : i already have a form divided in many html table
> with an anchor for each table, and i don't know how to do the same thing
> with the factory.
>
> Someone know how to fix the problem with the path and the filename ?
>
> Thx guys !
>
> Le mercredi 16 décembre 2015 15:55:26 UTC+1, Anthony a écrit :
>>
>> On Wednesday, December 16, 2015 at 4:53:41 AM UTC-5, xmarx wrote:
>>>
>>> in controller:
>>>
>>> def index():
>>> import os
>>> form=SQLFORM.factory(Field('name'),Field('file',
>>> 'upload',uploadfolder=os.path.join(request.folder,'uploads')))
>>> if form.process().accepted:
>>> request.flash='file uploaded!'
>>> return dict(form=form)
>>>
>>>
>> The only problem with using SQLFORM.factory to handle file uploads is
>> that it will use the DAL upload mechanism to rename the file (including a
>> random UUID segment). Because there is no database table storing the new
>> filename, it will now be difficult to retrieve the file, as you will not
>> know the filename (you would have to scan the whole directory and decode
>> all of the base-16-encoded parts of the filenames to retrieve the original
>> filenames).
>>
>> Anthony
>>
>
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