I suppose you want to return several positions that match (domain ==
session.target_domain) then you must not use return (as it escapes the loop
and exits the function scope). You should collect all your matches in a list
and the return the list in the end. Something like:
def check():
result_list = []
for target_keyword in session.keywords.split(','):
...
...
...
for idx, res in enumerate(results):
...
...
if domain == session.target_domain:
a_str = "Your google position is %d for keyword '%s' on domain
%s" \
% (idx+1, target_keyword,
session.target_domain)
result_list.append(a_str)
# Now you can return the list
return result_list
HTH
On Wed, May 12, 2010 at 2:34 AM, Andrew Evans <evans.d.and...@gmail.com>wrote:
> Hello I have a problem. I have code written for web2py that has two
> functions, the problem is in the looping of the second function. it
> only executes the loop once. Is there anyway I can continue looping
>
> def check():
> for target_keyword in session.keywords.split(','):
> gs = GoogleSearch(target_keyword)
> gs.results_per_page = int(session.results_per_page_num)
> results = gs.get_results()
> for idx, res in enumerate(results):
> parsed = urlparse(res.url)
> domain = mk_nice_domain(parsed.netloc)
> if domain == session.target_domain:
> return dict(search=build("Your google position is %d
> for keyword '%s' on domain %s" % (idx+1,
> target_keyword, session.target_domain)))
>
> Thanks if you can help
>
>
