No problem, it happens to everyone. :-) Anthony
On Tuesday, May 15, 2012 6:33:59 PM UTC-4, Gerald Klein wrote: > > OK, This is the post where I make a total fool out of myself, my contrite > apologies. I don't know if I had edited it to many times and was just not > seeing it. At the end of the day when I read the email and opened the code > there it was. I even recoded the previous part and it worked fine. Once > again I apologize and I do appreciate all your help. > > thanks > > --jerry > > On Tuesday, May 15, 2012 1:33:05 PM UTC-5, Anthony wrote: >> >> outside of the string passed to the message variable in the call to dict >>> my code is exactly the same, I didn't have any luck with the version above >>> this so I coded this instead. As far as the syntax error, I would be happy >>> to know where it is as I can't see it. And yes the trace is pointing to a >>> piece of code that doesn't show in my file. >>> non-keyword arg after keyword arg (default.py, line 14) >>> and line 14 is the last line of my code that I am showing here. >>> *return dict(message="hello", session.counter)* >>> >> Yes, that's the syntax error that several people have now pointed out to >> you. You have passed session.counter to dict() as a non-keyword argument >> (and it only takes keyword arguments, where the argument names become the >> dict keys). You have mis-copied that line from the book -- it should be: >> >> return dict(message="Hello from MyApp", counter=session.counter) >> >> >> Anthony >> >
