Hi,

Did you try using .ascs() instead of .asc() and .append() instead of .dot()?

Farrukh

Sent from my iPhone

On 14, دسمبر 2010, at 8:02 PM, Theodore Petrosky <[email protected]> wrote:

> Why does this work:
> 
> ERXSortOrderings newOrdering = 
> ERXSortOrdering.sortOrderingWithKey("parentCompany.parentCompanyName", 
> ERXSortOrdering.CompareAscending).then(Client.CLIENT_NAME.asc());
> 
> but this doesn't: 
> 
> ERXSortOrderings newOrdering1 = 
> ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
> 
> Here is the error: The method sortOrderingWithKey(String, NSSelector) in the 
> type ERXSortOrdering is not applicable for the arguments 
> (ERXSortOrdering.ERXSortOrderings)
> 
> ERXSortOrderings newOrdering2 = 
> ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
> 
> ERXSortOrderings newOrdering2 = 
> ERXSortOrdering.sortOrderingWithKey(ParentCompany.PARENT_COMPANY_NAME.asc().then(Client.CLIENT_NAME.asc());
> 
> As long as I start out with "string, selector" then I can chain - then, then, 
> etc. 
> 
> I must have some deep seated misunderstanding of ERXSortOrderings and how to 
> create it.
> 
> this one works beautifully: (except on closer examination, I don't understand 
> why it works with the parenthesis around the first element)
> 
> ERXSortOrderings newOrdering = 
> ERXSortOrdering.sortOrderingWithKey("version.job.primaryKey", 
> ERXSortOrdering.CompareAscending)
>        .then(Invoice.VERSION.dot(Version.ITEM_INDEX).asc())
>        .then(Invoice.VERSION.dot(Version.SUB_VERSION_NUMBER).asc())
>        .then(Invoice.VERSION.dot(Version.REVISION_NUMBER).asc())
>        .then(Invoice.INVOICE_DATE.asc() );
> 
> 
> Ted
> 
> 
> 
> 
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