.asc() = singular form, .ascs() = plural form, so

ERXSortOrdering = one of them, singular
ERXSortOrderings = plural, array subclass

ERXSortOrdering sortOrdering = Person.NAME.asc()
ERXSortOrderings sortOrderingS = Person.NAME.ascs()

you can also do:

ERXSortOrderings sortOrderingS = Person.NAME().asc().array()

ms

On Dec 14, 2010, at 12:33 PM, Theodore Petrosky wrote:

> One last item,
> 
> 
> ERXSortOrderings is an mutablearray of EOSortOrderings, but the array cannot 
> have one item.
> 
> ERXSortOrderings theCompanyOrder = ParentCompany.PARENT_COMPANY_NAME.asc();
> is not good. however, 
> 
> ERXSortOrdering theCompanyOrder = ParentCompany.PARENT_COMPANY_NAME.asc();
> NSArray<EOSortOrdering> companySort = new 
> NSArray<EOSortOrdering>(theCompanyOrder);
> parentCompanyDG.setSortOrderings(companySort);
> is good.
> 
> obviously parentCompanyDG is an ERXDisplayGroup.
> 
> 
> Is there a reason that I can not create an ERXSortOrderings with only one 
> item?
> 
> Ted
> 
> 
> 
> --- On Tue, 12/14/10, Mike Schrag <[email protected]> wrote:
> 
>> From: Mike Schrag <[email protected]>
>> Subject: Re: ERXSortOrderings ?
>> To: "Theodore Petrosky" <[email protected]>
>> Cc: [email protected]
>> Date: Tuesday, December 14, 2010, 12:09 PM
>> .asc() IS a sort ordering, you can't
>> pass it to sortorderingwithkey  because it's not a key
>> it's a sort ordering.
>> 
>> just get rid of ERXSortOrdering.sortOrderingWithKey
>> entirely and use key.asc().then(whatever).
>> 
>> ms
>> 
>> On Dec 14, 2010, at 12:02 PM, Theodore Petrosky wrote:
>> 
>>> Why does this work:
>>> 
>>> ERXSortOrderings newOrdering =
>> ERXSortOrdering.sortOrderingWithKey("parentCompany.parentCompanyName",
>> ERXSortOrdering.CompareAscending).then(Client.CLIENT_NAME.asc());
>>> 
>>> but this doesn't: 
>>> 
>>> ERXSortOrderings newOrdering1 =
>> ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
>>> 
>>> Here is the error: The method
>> sortOrderingWithKey(String, NSSelector) in the type
>> ERXSortOrdering is not applicable for the arguments
>> (ERXSortOrdering.ERXSortOrderings)
>>> 
>>> ERXSortOrderings newOrdering2 =
>> ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
>>> 
>>> ERXSortOrderings newOrdering2 =
>> ERXSortOrdering.sortOrderingWithKey(ParentCompany.PARENT_COMPANY_NAME.asc().then(Client.CLIENT_NAME.asc());
>>> 
>>> As long as I start out with "string, selector" then I
>> can chain - then, then, etc. 
>>> 
>>> I must have some deep seated misunderstanding of
>> ERXSortOrderings and how to create it.
>>> 
>>> this one works beautifully: (except on closer
>> examination, I don't understand why it works with the
>> parenthesis around the first element)
>>> 
>>> ERXSortOrderings newOrdering =
>> ERXSortOrdering.sortOrderingWithKey("version.job.primaryKey",
>> ERXSortOrdering.CompareAscending)
>>>        
>> .then(Invoice.VERSION.dot(Version.ITEM_INDEX).asc())
>>>        
>> .then(Invoice.VERSION.dot(Version.SUB_VERSION_NUMBER).asc())
>>>        
>> .then(Invoice.VERSION.dot(Version.REVISION_NUMBER).asc())
>>>        
>> .then(Invoice.INVOICE_DATE.asc() );
>>> 
>>> 
>>> Ted
>>> 
> 
> 
> 
> 

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