I attached the exception and this is the code I use to build the list:

add (zimmerartenList = new ListView ("zimmerartenList",
termin.getTerminDetails()) {

                private static final long serialVersionUID =
2623213955857979457L;

                @Override
                protected void populateItem(ListItem item) {
                    final TerminDetail terminDetail = (TerminDetail)
item.getModelObject();
                   
                    if( terminDetail.getFreieKontingente() > 0 ) {
                        item.add(new Label("zimmerart",
terminDetail.getZimmerart()));
                        item.add(new DropDownChoice ("paxProZimmerart",
terminDetail.getMoeglichePaxAnzahlen()));
                    }
                }
            });



Johan Compagner wrote:

> what kind of exception?
>
>
> Johannes Fahrenkrug wrote:
>
>> Hi,
>>
>> I'm new to Wicket and I have a question. I need to generate and display
>> a List of DropDownChoices. This is the scenario:
>> I have different room types and for every room type I have certain
>> vacancies. So I need to have something like this:
>>
>> Double room   - [Choose one               ]
>>                              [2                             ]
>>                              [4                             ]
>>                              [6                             ]
>>
>> Single room      -[Choose one              ]
>>                              [1                            ]
>>                              [2                             ]
>>                              [3                             ]
>>                              [4                            ]
>>
>>
>> I already managed to display that (with a list view and a DropDownChoice
>> attached to each item). But when I want to submit the form, I get an
>> exception.
>>
>> What would be The Right Thing to do?
>>
>> Thank you so much!
>>
>> - Johannes
>>
>>
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>
>
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