Sorry to bother you but something is not clear to me regarding this process..
Ok, lets sat I have two internal disks (73gb each) and I am mirror them... now I
want to replace those two mirrored disks into one LUN that is on SAN and it is
around 100gb. Now I do meet one requirement of having more than 73gb of storage
but do I need only something like 73gb at minimum or do I actually need two luns
of 73gb or more since I have it mirrored?
My goal is simple to move data of two mirrored disks into one single SAN
device... Any ideas if what I am planning to do is duable? or do I need to use
zfs send and receive and just update everything and switch when I am done?
or do I just add this SAN disk to the existing pool and then remove mirror
somehow? I would just have to make sure that all data is off that disk... is
there any option to evacuate data off that mirror?
here is what I exactly have:
bash-3.00# zpool list
NAME SIZE USED AVAIL CAP HEALTH ALTROOT
mypool 68G 52.9G 15.1G 77% ONLINE -
bash-3.00# zpool status
pool: mypool
state: ONLINE
scrub: none requested
config:
NAME STATE READ WRITE CKSUM
mypool ONLINE 0 0 0
mirror ONLINE 0 0 0
c1t2d0 ONLINE 0 0 0
c1t3d0 ONLINE 0 0 0
errors: No known data errors
bash-3.00#
On Tue, 29 May 2007, Cyril Plisko wrote:
On 5/29/07, Krzys <[EMAIL PROTECTED]> wrote:
Hello folks, I have a question. Currently I have zfs pool (mirror) on two
internal disks... I wanted to connect that server to SAN, then add more
storage
to this pool (double the space) then start using it. Then what I wanted to
do is
just take out the internal disks out of that pool and use SAN only. Is
there any
way to do that with zfs pools? Is there any way to move data from those
internal
disks to external disks?
You can "zpool replace" your disks with other disks. Provided that you have
same amount of new disks and they are of same or greater size
--
Regards,
Cyril
!DSPAM:122,465c515921755021468!
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