On Tuesday 09 March 2004 01:58 pm, Ian Beatty wrote: > This has to be an easy one.
Good, I'll take it. ;-) > From within my Python-based product's code, how do I get access to the > product's directory on the filesystem? os.getcwd() seems to provide the > working directory of the shell used to launch Zope, at least when running > in debug mode. This isn't actually Zope specific; you can easily get the directory a module lives in using this: import os here = os.path.dirname(os.path.abspath(__file__)) The variable "here" will hold a string with an absolute path to the directory containing the source file for your module (named by __file__). The call to os.path.abspath() isn't strictly necessary, but protects against future calls to os.chdir() (though not past calls!) in case the module was loaded from directory named by a relative directory on sys.path. You can do this just once at module scope; there's no need to recompute this each time you need it. -Fred -- Fred L. Drake, Jr. <fred at zope.com> PythonLabs at Zope Corporation _______________________________________________ Zope-Dev maillist - [EMAIL PROTECTED] http://mail.zope.org/mailman/listinfo/zope-dev ** No cross posts or HTML encoding! ** (Related lists - http://mail.zope.org/mailman/listinfo/zope-announce http://mail.zope.org/mailman/listinfo/zope )