There is also a convenience function for this in Zope: from Globals import package_home here = package_home(globals())
- C On Tue, 2004-03-09 at 14:16, Fred Drake wrote: > On Tuesday 09 March 2004 01:58 pm, Ian Beatty wrote: > > This has to be an easy one. > > Good, I'll take it. ;-) > > > From within my Python-based product's code, how do I get access to the > > product's directory on the filesystem? os.getcwd() seems to provide the > > working directory of the shell used to launch Zope, at least when running > > in debug mode. > > This isn't actually Zope specific; you can easily get the directory a module > lives in using this: > > import os > here = os.path.dirname(os.path.abspath(__file__)) > > The variable "here" will hold a string with an absolute path to the directory > containing the source file for your module (named by __file__). The call to > os.path.abspath() isn't strictly necessary, but protects against future calls > to os.chdir() (though not past calls!) in case the module was loaded from > directory named by a relative directory on sys.path. > > You can do this just once at module scope; there's no need to recompute this > each time you need it. > > > -Fred _______________________________________________ Zope-Dev maillist - [EMAIL PROTECTED] http://mail.zope.org/mailman/listinfo/zope-dev ** No cross posts or HTML encoding! ** (Related lists - http://mail.zope.org/mailman/listinfo/zope-announce http://mail.zope.org/mailman/listinfo/zope )
