Something is not right there unless the 48 volt power supply can be
drawn down. Ohm's law is two equations.
P = I*E and E = I*R
In words power equals current times voltage and voltage equals current
times resistance.
P = I*E ( 6 = I * 48 )
Solve for I ( 6/48 = I ) = .125 amps
E = I*R ( 48 = .125 * R )
Solve for R ( 48/.125 = R ) = 384 oms
E = I*R ( 48 = I * 100 )
Solve for I ( 48/100 = I ) = .48 amps
You can make it work if the 100 ohm load pulls the power supply voltage
down.
bp
<part15sbs{at}gmail{dot}com>
On 3/9/2017 3:05 PM, Chuck McCown wrote:
Had a fun afternoon.
Solve this.... and give the general formula...
48 volt power supply
100 ohm wire resistance to the load.
6 watt load.
Took me some time. Not trivial.
