The idea would be to remove the power source entirely and find the
thevenin resistance.
So is the resistance changing or is the voltage?
On 3/9/2017 7:29 PM, Chuck McCown wrote:
But what is the Thevenin equivalent of a constant POWER component?
Read my reply to Bill, there is feedback. The voltage drop of the
resistor changes the current drawn by the load which changes the
voltage drop of the resistor and so on.
*From:* David Milholen
*Sent:* Thursday, March 09, 2017 6:24 PM
*To:* [email protected]
*Subject:* Re: [AFMUG] Ohms law
This is straight out of my Dc circuit analysis book from college.
https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/thevenins-theorem/
I kinda thought my voltage was a bit off but the 100ohm is not a fixed
value.
I just used Watts/volts to get my current. W/V=I
I then used the current to get the voltage drop across the loop
I*R=V drop
Its been a while for the thevenins therom but if i do a little study I
think I could get it.
On 3/9/2017 5:28 PM, Chuck McCown wrote:
But what is the formula?
�
*From:* Dave
*Sent:* Thursday, March 09, 2017 4:20 PM
*To:* [email protected]
*Subject:* Re: [AFMUG] Ohms law
�
Current =.125A at load
Voltage=35.5 at load
If my current is correct then I should be on point.
Otherwise I would use Thevenins Therom to get closer.
On 03/09/2017 05:08 PM, Chuck McCown wrote:
The questions are:
What is the current and voltage on the load.�
�
*From:* Chuck McCown
*Sent:* Thursday, March 09, 2017 4:05 PM
*To:* [email protected]
*Subject:* [AFMUG] Ohms law
�
Had a fun afternoon.�
�
Solve this.... and give the general formula...
�
48 volt power supply
100 ohm wire resistance to the load.
6 watt load.
�
Took me some time.� Not trivial.�
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