This is what I sent originally:
bp
<part15sbs{at}gmail{dot}com>
On 3/9/2017 5:06 PM, Bill Prince wrote:
Iiiiieee!! What happened to that?
bp
<part15sbs{at}gmail{dot}com>
On 3/9/2017 5:04 PM, Bill Prince wrote:
Something is not right there unless the 48 volt power supply can be
drawn down. Ohm's law is two equations.
P = I*E�� and� E = I*R
In words power equals current times voltage and voltage equals
current times resistance.
P = I*E�� ( 6 = I * 48 )
Solve for I�� ( 6/48 = I ) = .125 amps
E = I*R ( 48 = .125 * R )
Solve for R� ( 48/.125 = R ) = 384 oms
E = I*R� ( 48 = I * 100 )
Solve for I� ( 48/100 = I ) = .48 amps
You can make it work if the 100 ohm load pulls the power supply
voltage down.
bp
<part15sbs{at}gmail{dot}com>
On 3/9/2017 3:05 PM, Chuck McCown wrote:
Had a fun afternoon.�
�
Solve this.... and give the general formula...
�
48 volt power supply
100 ohm wire resistance to the load.
6 watt load.
�
Took me some time.� Not trivial.�
