On Tue, Jul 1, 2008 at 10:25 PM, Charles Reiss <[EMAIL PROTECTED]> wrote: > The big issue is that under the hypothetical scheme, the effective > vote power P of sets of players has the property P(S u T) - P(S) = > VVLOD(T) (for |S| >=2). Thus, the effective bargaining power every > non-empty set of players (with any other non-empty set of players) is > always equal to their (summed) VVLOD. That's boring.
Mm, a political party where you always have to endorse the party's vote, whatever that may be, would be interesting, I think. --Ivan Hope CXXVII
