I am not sure if constant space requirement is possible. But we can do it
with O(k) space complexity.
Maintain a max heap of k elements. For each of the n*m sums add it to the
heap (if it ain't full with k elements) or replace the root and heapify if
the sum is lesser than the root.

Finally the root will have the k'th smallest sum.

But this would require O(n*m*log k) time complexity.

On Sat, Sep 5, 2009 at 5:10 AM, ankur aggarwal <ankur.mast....@gmail.com>wrote:

> @dufus..
> if there is constant space requirement then ??
> wat will be your soln ??
>
>
> On Sat, Sep 5, 2009 at 12:35 PM, Dufus <rahul.dev.si...@gmail.com> wrote:
>
>>
>> It seems EXTRACT_MIN for Z[n^2] can be done in O(n) time.
>> http://lyle.smu.edu/~saad/courses/cse3358/ps5/problemset5sol.pdf<http://lyle.smu.edu/%7Esaad/courses/cse3358/ps5/problemset5sol.pdf>
>>
>> Then using it we can find the kth smallest element in O(nk) time.
>>
>> _dufus
>>
>>
>> On Sep 4, 10:03 pm, ankur aggarwal <ankur.mast....@gmail.com> wrote:
>> >  Find nth smallest inO(n) Given two arrays of length n in sorted order
>> > X[n] & Y[n].
>> > Now make another array Z[n^2]={such that z belongs to X+Y}.
>> > AS all possible sum of x+y is there in Z. You have to give the nth
>> smallest
>> > no of Z in O(n) time.
>> > Space complexity : No bound on it. But try to optimize it if possible.
>>
>>
>>
>
> >
>


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