Dave, we don't remove (3,3)...
min_query will return 3 stored at the top..ie (9,3)..
pop will remove (9,3).. not (3,3)

On Thu, Oct 8, 2009 at 8:47 PM, sharad kumar <aryansmit3...@gmail.com> wrote:
> 3 is min element then y to return 5??if  u remove 9,3
> 3 at tos 3 is min so y to remove 5 borther dave
>
> On Thu, Oct 8, 2009 at 8:37 PM, Dave <dave_and_da...@juno.com> wrote:
>>
>> Satyam, let's work your example in detail. We've pushed your data onto
>> the stack, and now we start popping.
>>
>> (6,6),(5,5),(10,5),(3,3),(9,3),(1,1), so remove the (1,1) and return
>> 1.
>> (6,6),(5,5),(10,5),(3,3),(9,3) so remove (3,3) and return 3.
>> (6,6),(5,5),(10,5),(9,3). Now what? How do we find (5,5) to return 5?
>>
>> Dave
>>
>>
>> On Oct 8, 6:15 am, harit agarwal <agarwalha...@gmail.com> wrote:
>> > @manisha
>> > i think u didn't get my point
>> >
>> > every time it will return the different value
>> > ex
>> > values to be pushed 6,5,10,3,9,1
>> > now push(a,b) a=element b=minimum value pushed till now
>> > (6,6)
>> > (6,6),(5,5)
>> > (6,6),(5,5),(10,5)
>> > (6,6),(5,5),(10,5),(3,3)
>> > (6,6),(5,5),(10,5),(3,3),(9,3)
>> > (6,6),(5,5),(10,5),(3,3),(9,3),(1,1)
>> >
>> > now start popping
>> > (1,1) min in stack=1
>> > (9,3) min in stack =3
>> > similarly
>> > last (6,6) min in stack=6
>> >
>> > so everytime u get min in O(1)
>>
>
>
> >
>

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