i thought the same way, but in this case 4 is being repeated twice, but is
not nullified!!!!

it is ctually getting nullified, but it is indeed contributing to bit 2 so
how do i rule out 4 here?


Best Regards
Ashish Goel
"Think positive and find fuel in failure"
+919985813081
+919966006652


On Wed, Jul 7, 2010 at 10:17 AM, Anand <anandut2...@gmail.com> wrote:

> if we xor all elements of the array, then the element which are repeated
> twice and multiple of two gets nullify and what left is the number which got
> repeated once and thrice. if we can find the number which got repeated once,
> then we can xor that number from the total xor value to get the element
> which got repeated thrice.
>
>
> On Tue, Jul 6, 2010 at 9:37 PM, Ashish Goel <ashg...@gmail.com> wrote:
>
>> can i take this as a sample array?
>>
>> 1,1,2,2,3,3,4,4,4,5,5,5,5
>>
>> or
>>
>> 1,2,3,4,4,5,5,5
>>
>> ideally a bit map would suffice for identification of repeating numbers,
>> but the memory requirements shoot up
>>
>>
>> 0001
>> 0010
>> 0011
>> 0100
>> 0100
>> 0101
>> 0101
>> 0101
>>
>> xor result = 0101, how to proceed further..??
>>
>> Best Regards
>> Ashish Goel
>> "Think positive and find fuel in failure"
>> +919985813081
>> +919966006652
>>
>>
>> On Mon, Jul 5, 2010 at 7:18 PM, jalaj jaiswal 
>> <jalaj.jaiswa...@gmail.com>wrote:
>>
>>> Given an array of integers where some numbers repeat 1 time, some numbers
>>> repeat 2 times and only one number repeats 3 times, how do you find the
>>> number that repeat 3 times.
>>>
>>> can xor do something here ??
>>>
>>> --
>>> With Regards,
>>> Jalaj Jaiswal
>>> +919026283397
>>> B.TECH IT
>>> IIIT ALLAHABAD
>>>
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