you have misinterpreted the questn.. 1 simply means 1 occurences.... we have
to do this inplace

On Wed, Jul 7, 2010 at 10:37 AM, Ashish Goel <ashg...@gmail.com> wrote:

> i thought the same way, but in this case 4 is being repeated twice, but is
> not nullified!!!!
>
> it is ctually getting nullified, but it is indeed contributing to bit 2 so
> how do i rule out 4 here?
>
>
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
>
> On Wed, Jul 7, 2010 at 10:17 AM, Anand <anandut2...@gmail.com> wrote:
>
>> if we xor all elements of the array, then the element which are repeated
>> twice and multiple of two gets nullify and what left is the number which got
>> repeated once and thrice. if we can find the number which got repeated once,
>> then we can xor that number from the total xor value to get the element
>> which got repeated thrice.
>>
>>
>> On Tue, Jul 6, 2010 at 9:37 PM, Ashish Goel <ashg...@gmail.com> wrote:
>>
>>> can i take this as a sample array?
>>>
>>> 1,1,2,2,3,3,4,4,4,5,5,5,5
>>>
>>> or
>>>
>>> 1,2,3,4,4,5,5,5
>>>
>>> ideally a bit map would suffice for identification of repeating numbers,
>>> but the memory requirements shoot up
>>>
>>>
>>> 0001
>>> 0010
>>> 0011
>>> 0100
>>> 0100
>>> 0101
>>> 0101
>>> 0101
>>>
>>> xor result = 0101, how to proceed further..??
>>>
>>> Best Regards
>>> Ashish Goel
>>> "Think positive and find fuel in failure"
>>> +919985813081
>>> +919966006652
>>>
>>>
>>> On Mon, Jul 5, 2010 at 7:18 PM, jalaj jaiswal <jalaj.jaiswa...@gmail.com
>>> > wrote:
>>>
>>>> Given an array of integers where some numbers repeat 1 time, some
>>>> numbers repeat 2 times and only one number repeats 3 times, how do you find
>>>> the number that repeat 3 times.
>>>>
>>>> can xor do something here ??
>>>>
>>>> --
>>>> With Regards,
>>>> Jalaj Jaiswal
>>>> +919026283397
>>>> B.TECH IT
>>>> IIIT ALLAHABAD
>>>>
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-- 
With Regards,
Jalaj Jaiswal
+919026283397
B.TECH IT
IIIT ALLAHABAD

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