@jalaj

Are we looking for a better than )(nlogn) time and O(1) space
solution? What if our target?

If a solution is required simple, then as mentioned by Satya, sort the
numbers in O(nlogn) time and scan once in O(n) time. So we get the
number repeated 3 times in O(nlogn) time and O(1) space.

Sourav

On Jul 7, 7:36 pm, Priyanka Chatterjee <dona.1...@gmail.com> wrote:
> > I am sceptical whether any XOR solution  exits for your question. But if
> > the question is modified as :
>
> > *Only one number repeats once,* some no.s repeat twice and only one number
> > repeat thrice, here is the XOR solution for that.
>
> > suppose the sample array is A[]={1, 3,3,5,5,5, 7,7,8,8}
> > in the example 1 repeats once and 5 repeats thrice.
>
> > 1>let T= XOR( all elements)= 1^5. (all elements occurring even no of times
> > nullify)   -O(N)
>
> > (  let x=1, y=5
> > As we know the no. repeating once and the no. repeating thrice are unequal,
> > there must exist some bit 'k' such that x[k]!=y[k]. There may be more than
> > such bits in x and y. But one such bit certainly yields T[k]=1  after x^y)
>
> > 2> Now traverse along each bit of  T( in binary) from left or right and
> > consider  T[i] =1 which is encountered first. store it . let b=i;
> >  (O(M) time and O(M) space to store binary  if M is the bit length of T.)
>
> > 3> T1= XOR(all elements in given array having bit b as 1)..... (O(N)  time
> > and O(M) space) ( time is O(MN) but as M<=32 , complexity remain O(N))
>
> > 4> T0= XOR( all elements in given array having bit b as 0) (O(N) time and
> > O(M) space)
>
> >  One of (T1,T0) gives the no. that repeats once and the other gives the no
> > that repeats thrice.
>
> > 6> Now traverse the along array A and compute count for T1 and T0. The
> > count that equals 3 gives the corresponding no. repeating thrice. -O(N)
>
> >  Time complexity is O(N+M) . Linear
> > space complexity is O(M) to store binary form.
>
> > But this algo certainly fails if  more than one no. repeats once.
>
> --
> Thanks & Regards,
> Priyanka Chatterjee
> Final Year Undergraduate Student,
> Computer Science & Engineering,
> National Institute Of Technology,Durgapur
> Indiahttp://priyanka-nit.blogspot.com/- Hide quoted text -
>
> - Show quoted text -

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