Just add the number of the array and let the sum is S. Its complexity is
O(n).
Now XOR all elements of the array and say the result is X_SUM.Its complexity
is  O(n).
Now the duplicate element is = (S - X_SUM)/2

On Wed, Oct 20, 2010 at 4:14 PM, Asquare <anshika.sp...@gmail.com> wrote:

> @Anirvana - In context to the XOR method u suggested, could u plz
> explain why does it so happen.. ??
>
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-- 
   Mahesh Giri

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