Down two opposite sides of the board, except for the two squares on
the same end:
2x2: x x
- -
3x3: x - x
x - x
- - -
4x4: x - - x
x - - x
x - - x
- - - -
Dave
On Feb 4, 12:12 pm, Rahul Verma <rahulverma....@gmail.com> wrote:
> @king
> Can you pls told me that wat would be the position at where bishops
> might place in the 2X2, 3X3, 4X4 chessboard.....
>
> On Feb 4, 8:39 pm, subramania jeeva <subramaniaje...@gmail.com> wrote:
>
>
>
> > Use python for arithmetic operation of large numbers.. :)
>
> > Cheers
> > ~ Jeeva ~
>
> > On Fri, Feb 4, 2011 at 8:32 PM, Manmeet Singh <mans.aus...@gmail.com> wrote:
> > > C/C++ user : Take input in a char array or string(if using C++) : a
> > > now do string addition. : a = a + a;
> > > now do string substraction. : a = a - 2.
>
> > > Java user : Use BigInt class
>
> > > On Fri, Feb 4, 2011 at 8:12 PM, Logic King
> > > <crazy.logic.k...@gmail.com>wrote:
>
> > >> please help me solve the problem on SPOJ
>
> > >>https://www.spoj.pl/problems/BISHOPS/
>
> > >> The logic of the problem is very easy i.e. 2*n-2
> > >> but i am getting WA bcoz i am not able to deal with the large inputs.[?]
> > >> plz help me how to get this AC.........
>
> > >> #include<stdio.h>
> > >> int main()
> > >> {
> > >> long long int n,bmax;
> > >> while(scanf("%lld",&n)!=EOF)
> > >> {
> > >> if(n==1)
> > >> printf("%d\n",1);
> > >> else
> > >> {
> > >> bmax=(2*n)-2;
> > >> printf("%lld\n",bmax);
>
> > >> }
> > >> }
> > >> return 0;
> > >> }
>
> > >> --
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> > 325.png
> > < 1KViewDownload- Hide quoted text -
>
> - Show quoted text -
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