according to precedence

m= ++i || ++j && ++k
will become
m = ++i || (++j && ++k);                NOT this  m = (++i || ++j) && ++k;

first i gets incremented and since that gives a non-zero value the rest of
the statement is not executed.

On Tue, Jun 14, 2011 at 8:41 PM, nicks <crazy.logic.k...@gmail.com> wrote:

> anybody having idea about preference order ??
>
>
> On Tue, Jun 14, 2011 at 4:20 AM, nicks <crazy.logic.k...@gmail.com> wrote:
>
>> What about precedence order then.....
>> http://www.difranco.net/cop2220/op-prec.htm i mean acc. to precedence
>> order && should be evaluated before || in the second example....result
>> should be k=1,j=3 and i= -2
>>
>>
>> On Mon, Jun 13, 2011 at 11:41 AM, udit sharma <sharmaudit...@gmail.com>wrote:
>>
>>> hmm. Sry yr... Got it.. Thanx.. :) :)
>>>
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