first it checks Q if that is NOT true then it computes R else it doesn't.

this is the correct line .
On Tue, Jun 14, 2011 at 10:21 PM, snehi jain <snehijai...@gmail.com> wrote:

> that is what is happening here
> m = ++i || (++j && ++k);
>
> in C if       P = Q || R;
>
> first it checks Q if that is NOT true then it computes C else it doesn't.
>
> ++ is a unary operator so before the || and && operations can happen
> increment will take place. This justifies the higher precedence of ++
> operator.
>
> in the above example  i gets incremented to -2 first and then || operation
> is executed. i has a non-zero value therefore no computation is done for
> (++j && ++k); .
>
> keep initial value of i to -1 then  after m = ++i || (++j && ++k);
> statement
> i = 0 , j = 3 , k =1 and m =1
>
>
>
>
>
> On Tue, Jun 14, 2011 at 10:02 PM, nicks <crazy.logic.k...@gmail.com>wrote:
>
>> hmm...someone explain...me too confused :(
>>
>>
>> On Tue, Jun 14, 2011 at 9:14 AM, rahul dixit <dixit.rahu...@gmail.com>wrote:
>>
>>>
>>> bt increment operator has the higher precedence than || and &&
>>> so all the variables should be incremented  first then && and then ||
>>> should  be evaluated
>>> then how it is happening.plz explain
>>>
>>>
>>> rahul dixit
>>> Du-Mca
>>>
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>

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