that is what is happening here m = ++i || (++j && ++k); in C if P = Q || R;
first it checks Q if that is NOT true then it computes C else it doesn't. ++ is a unary operator so before the || and && operations can happen increment will take place. This justifies the higher precedence of ++ operator. in the above example i gets incremented to -2 first and then || operation is executed. i has a non-zero value therefore no computation is done for (++j && ++k); . keep initial value of i to -1 then after m = ++i || (++j && ++k); statement i = 0 , j = 3 , k =1 and m =1 On Tue, Jun 14, 2011 at 10:02 PM, nicks <crazy.logic.k...@gmail.com> wrote: > hmm...someone explain...me too confused :( > > > On Tue, Jun 14, 2011 at 9:14 AM, rahul dixit <dixit.rahu...@gmail.com>wrote: > >> >> bt increment operator has the higher precedence than || and && >> so all the variables should be incremented first then && and then || >> should be evaluated >> then how it is happening.plz explain >> >> >> rahul dixit >> Du-Mca >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
