const methods can only be called by constant objects. since in this case the
object is not constant it will call the normal method.
On Tue, Jul 12, 2011 at 10:24 PM, Aniket Dutta <aniketdutt...@gmail.com>wrote:
> @dheeraj: but the prototypes are same..... how u are calling it
> overloading plz explain
>
> On 7/12/11, dheeraj tyagi <dheeraj2...@gmail.com> wrote:
> > const means that it cannot be overloaded..i think due to that this is
> > happening.
> >
> > On Tue, Jul 12, 2011 at 9:26 PM, segfault <pawan1991ya...@gmail.com>
> wrote:
> >
> >> #include<iostream>
> >> using namespace std;
> >> class x{
> >> public:
> >> x() {}
> >>
> >> int func() const{
> >> cout<<"it is const function\n";
> >> }
> >>
> >> int func() {
> >> cout<<"it is simple functin\n";
> >> }
> >>
> >>
> >> };
> >> int main()
> >> {
> >> x a;
> >> a.func();
> >> return 0;
> >> }
> >>
> >> why cann't it take const function?
> >> explain it
> >>
> >> --
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> >>
> >
> >
> > --
> > With regards
> > Dheeraj Tyagi
> > 8197218001
> >
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With regards
Dheeraj Tyagi
8197218001
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