cant i invoke both simultaneously??
if i try to make two objects like
x const a;
x a;
then it gives error..can u explain plz.

On Jul 12, 9:55 pm, Sandeep Jain <sandeep6...@gmail.com> wrote:
> *const* in C++ is not exactly same as *final* in java. SO unlike java adding
> the keyword const to a function does not affect overriding.
> Infact, adding in C++ const functions ==> that they will not modify any
> member of the class.
> non-const functions cannot be invoked by const objects.
>
> Try making object 'a' as const i.e.
> const x a;
> and then invoke f(), it should invoke the correct version.
>
> Note that C++ allows function overloading based on const-ness.
> Refer (Const function 
> section)http://www.cprogramming.com/tutorial/const_correctness.html
> Also, subscript operators generally come in pairs, 
> Referhttp://www.parashift.com/c++-faq-lite/operator-overloading.html#faq-1...http://www.parashift.com/c++-faq-lite/const-correctness.html#faq-18.12
>
> Regards,
> Sandeep Jain
>
> On Tue, Jul 12, 2011 at 10:09 PM, dheeraj tyagi <dheeraj2...@gmail.com>wrote:
>
>
>
>
>
>
>
> > const means that it cannot be overloaded..i think due to that this is
> > happening.
>
> > On Tue, Jul 12, 2011 at 9:26 PM, segfault <pawan1991ya...@gmail.com>wrote:
>
> >> #include<iostream>
> >> using namespace std;
> >> class x{
> >> public:
> >> x() {}
>
> >> int  func() const{
> >> cout<<"it is const function\n";
> >> }
>
> >> int func() {
> >> cout<<"it is simple functin\n";
> >> }
>
> >> };
> >> int main()
> >> {
> >> x a;
> >> a.func();
> >> return 0;
> >> }
>
> >> why cann't it take const function?
> >> explain it
>
> >> --
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>
> > --
> > With regards
> > Dheeraj Tyagi
> > 8197218001
>
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