@Gaurav: The best solution would be to manipulate the given BTree in
place and get the BST. We don't need a separate tree but convert the
existing one using the same space occupied by nodes of BT already in
BST.

On Jul 19, 2:06 am, Gaurav Popli <gpgaurav.n...@gmail.com> wrote:
> cant we just do....traverse using recursion and instead of printing it
> just pass to function which is making BST....??
> and is this right as someone above said first sort it and then make BST...
> dont we want that root of both Tree to be same or something like that...??
>
>
>
> On Tue, Jul 19, 2011 at 2:17 AM, Dumanshu <duman...@gmail.com> wrote:
> > @Balaji: for third question, were u asked to write the code?
>
> > On Jul 18, 10:04 pm, Balaji S <balaji.ceg...@gmail.com> wrote:
> >> wats the mistake..
>
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