@Samm : Im not able to understand ur logic...im not getting the correct
ans...can u explain the working taking n as 7?
On Sat, Jul 30, 2011 at 12:25 PM, SAMM <somnath.nit...@gmail.com> wrote:
> Single bit shift...
>
> int divide(int n)
> {
> n-=1;
> n>>=1;
> return n;
> }
>
> On 7/30/11, tech rascal <techrascal...@gmail.com> wrote:
> > hw will u get the ans on repeated subtraction from the sum of the
> digits??
> > I mean ....if I hv 2 divide 27 by 3 thn first I'll find sum of the digits
> > i.e, 2+7=9
> > then I'll apply repeated subtraction on 9, so hw will i reach to the
> ans??
> >
> >
> > On Sat, Jul 30, 2011 at 10:05 AM, nivedita arora <
> > vivaciousnived...@gmail.com> wrote:
> >
> >>
> >> @brijesh-
> >> itoa basically converts integer to string ..we are using the fact tht
> >> a number is multiple of 3 if its sum is multiple of 3
> >> . we have int as string and we can traverse it ..for each character
> >> apply
> >> int sum+=*c-'0' (ankur missed the star :P)
> >> then on sum we use repeated subtraction...i hope its clear .
> >>
> >> we are using all this just coz we have to use itoa ..otherwise there
> >> are more methods (check my frst post )
> >>
> >>
> >> On Jul 30, 4:34 am, brijesh <brijeshupadhyay...@gmail.com> wrote:
> >> > @ankur I didnt get this... could u or anyone please elaborate!
> >> >
> >> > On Jul 30, 12:43 am, Ankur Khurana <ankur.kkhur...@gmail.com> wrote:
> >> >
> >> >
> >> >
> >> >
> >> >
> >> >
> >> >
> >> > > when you use itoa , what you get is a string. get the sum of all the
> >> digits
> >> > > , using c-'0' and then use repeated subtraction . . .
> >> >
> >> > > On Sat, Jul 30, 2011 at 1:01 AM, sukhmeet singh <
> >> sukhmeet2...@gmail.com>wrote:
> >> >
> >> > > > repeated subtraction !!
> >> >
> >> > > > On Sat, Jul 30, 2011 at 12:52 AM, nivedita arora <
> >> > > > vivaciousnived...@gmail.com> wrote:
> >> >
> >> > > >> Without using /,% and * operators. write a function to divide a
> >> number
> >> > > >> by 3. itoa() function is available.
> >> >
> >> > > >> all i cn thnk of is to use shift operator and addition ,
> >> x/3=e^(logx-
> >> > > >> log3) or repetitive subtraction
> >> >
> >> > > >> but none of them uses itoa() ..ne idea how its done?
> >> > > >> thnks !
> >> >
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> >> > > Ankur Khurana
> >> > > Computer Science
> >> > > Netaji Subhas Institute Of Technology
> >> > > Delhi.
> >>
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> --
> Somnath Singh
>
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--
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi
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