yeah if it was a divisibility test then the question would have been too
trivial ..
the last digit after doing itoa will be the remainder .

On Sat, Jul 30, 2011 at 11:52 AM, nivedita arora <
vivaciousnived...@gmail.com> wrote:

> i think solution of ankit is right !
> sorry even i forgot tht que ws not divisibility test ..but to get
> quotient :-|
>
> On Jul 30, 10:03 pm, Ankur Khurana <ankur.kkhur...@gmail.com> wrote:
> > @roopam : i got the question all wrong. . .
> >
> > On Sat, Jul 30, 2011 at 10:01 PM, Roopam Poddar <mailroo...@gmail.com
> >wrote:
> >
> >
> >
> >
> >
> >
> >
> >
> >
> > > The objective is to divide the number by 3 and not just check for it's
> > > divisibility.
> > > Adding the digits using itoa() and then repeated subtraction will check
> for
> > > it's divisibility by 3 and not give us the quotient.
> > > To get that you will have to carry out repeated subtraction on the
> number
> > > anyway.
> > > So whats the point?
> >
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> > --
> > Ankur Khurana
> > Computer Science
> > Netaji Subhas Institute Of Technology
> > Delhi.
>
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-- 
The more you sweat in the field, the less you bleed in war."

Ankit Minglani
NITK Surathkal

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