@ankit: not the last digit..!!
it will be (last digit -3) or (last digit -3-3) whichever is positive..

:)

On 7/31/11, Ankit Minglani <ankit.mingl...@gmail.com> wrote:
> yeah if it was a divisibility test then the question would have been too
> trivial ..
> the last digit after doing itoa will be the remainder .
>
> On Sat, Jul 30, 2011 at 11:52 AM, nivedita arora <
> vivaciousnived...@gmail.com> wrote:
>
>> i think solution of ankit is right !
>> sorry even i forgot tht que ws not divisibility test ..but to get
>> quotient :-|
>>
>> On Jul 30, 10:03 pm, Ankur Khurana <ankur.kkhur...@gmail.com> wrote:
>> > @roopam : i got the question all wrong. . .
>> >
>> > On Sat, Jul 30, 2011 at 10:01 PM, Roopam Poddar <mailroo...@gmail.com
>> >wrote:
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > > The objective is to divide the number by 3 and not just check for it's
>> > > divisibility.
>> > > Adding the digits using itoa() and then repeated subtraction will
>> > > check
>> for
>> > > it's divisibility by 3 and not give us the quotient.
>> > > To get that you will have to carry out repeated subtraction on the
>> number
>> > > anyway.
>> > > So whats the point?
>> >
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>> > --
>> > Ankur Khurana
>> > Computer Science
>> > Netaji Subhas Institute Of Technology
>> > Delhi.
>>
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>>
>
>
> --
> The more you sweat in the field, the less you bleed in war."
>
> Ankit Minglani
> NITK Surathkal
>
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