A[3][4] wud be in the 4th row...so strtung address of 4th row wud be 46..and
thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 rows + 16 fr
the 4th elemnet so 196

On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri <akshaykhatri...@gmail.com>wrote:

> how is that 49 bytes and 196 bytes
> shouldn't it be 44 and 176 bytes respectively
>
>
> On 6 August 2011 23:26, Ram Chauhan <rb.chau...@gmail.com> wrote:
>
>> 1049 and 1098
>>
>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg <aditi.garg.6...@gmail.com>wrote:
>>
>>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>>
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-- 
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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