@all : I Think the output depends on whether it is row major or column
major representation in memory .
Does he row major or column major representations matter
in calculations above???
On Aug 6, 11:49 pm, aditi garg <aditi.garg.6...@gmail.com> wrote:
> oh @ akshay y ru doing 10x4??? 10 is the no of rows not the columns so it
> shud be 15x3+4...and by multiplying by 4(in 10x4) ur taking it to the 5th
> row ie A[4][4] its only A[3][4]...
> i hope its clear now....
>
> On Sun, Aug 7, 2011 at 12:14 AM, akshay khatri
> <akshaykhatri...@gmail.com>wrote:
>
>
>
>
>
>
>
>
>
>
>
> > On 6 August 2011 23:56, aditi garg <aditi.garg.6...@gmail.com> wrote:
>
> >> @akshay: what i meant ws suppose the array strted from 0000 in
> >> decimal...so A[3][4] wud be at 0049 and B[3][4] will be at 0196
> >> convert dese 2 values to hex it gives 31 and C4 respectively...now base
> >> address is 1000 and 2000 instead if 0000 so add the base address and u get
> >> the ans 1031 and 20C4...i hope its clear now...
>
> > I still don't get how you got the figures of 49 and 196
>
> > I calculated as follows
> > A[3][4] = 10x4 + 4 = 44 bytes
> > B[3][4] = (10x4 + 4 )x4 = 176
>
> >> On Sat, Aug 6, 2011 at 11:49 PM, akshay khatri <akshaykhatri...@gmail.com
> >> > wrote:
>
> >>> On 6 August 2011 23:40, aditi garg <aditi.garg.6...@gmail.com> wrote:
>
> >>>> A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
> >>>> 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3
> >>>> rows
> >>>> + 16 fr the 4th elemnet so 196
>
> >>> How does it start from 46 and 180 ?
> >>> as per my knowledge, 0x1000 = 4096 and 0x2000 is 8192
>
> >>>> On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri <
> >>>> akshaykhatri...@gmail.com> wrote:
>
> >>>>> how is that 49 bytes and 196 bytes
> >>>>> shouldn't it be 44 and 176 bytes respectively
>
> >>>>> On 6 August 2011 23:26, Ram Chauhan <rb.chau...@gmail.com> wrote:
>
> >>>>>> 1049 and 1098
>
> >>>>>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg <
> >>>>>> aditi.garg.6...@gmail.com> wrote:
>
> >>>>>>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
> >>>>>>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
> >>>>>>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>
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> >>>> --
> >>>> Aditi Garg
> >>>> Undergraduate Student
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> >> --
> >> Aditi Garg
> >> Undergraduate Student
> >> Electronics & Communication Divison
> >> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> >> Sector 3, Dwarka
> >> New Delhi
>
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> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
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