@aditi : I Think the output depends on whether it is row major or column
major representation in memory .
Does he row amjor or column
On Sun, Aug 7, 2011 at 12:19 AM, aditi garg <aditi.garg.6...@gmail.com>wrote:
> oh @ akshay y ru doing 10x4??? 10 is the no of rows not the columns so it
> shud be 15x3+4...and by multiplying by 4(in 10x4) ur taking it to the 5th
> row ie A[4][4] its only A[3][4]...
> i hope its clear now....
>
>
>
> On Sun, Aug 7, 2011 at 12:14 AM, akshay khatri
> <akshaykhatri...@gmail.com>wrote:
>
>>
>>
>> On 6 August 2011 23:56, aditi garg <aditi.garg.6...@gmail.com> wrote:
>>
>>> @akshay: what i meant ws suppose the array strted from 0000 in
>>> decimal...so A[3][4] wud be at 0049 and B[3][4] will be at 0196
>>> convert dese 2 values to hex it gives 31 and C4 respectively...now base
>>> address is 1000 and 2000 instead if 0000 so add the base address and u get
>>> the ans 1031 and 20C4...i hope its clear now...
>>>
>>
>> I still don't get how you got the figures of 49 and 196
>>
>> I calculated as follows
>> A[3][4] = 10x4 + 4 = 44 bytes
>> B[3][4] = (10x4 + 4 )x4 = 176
>>
>>>
>>>
>>> On Sat, Aug 6, 2011 at 11:49 PM, akshay khatri <
>>> akshaykhatri...@gmail.com> wrote:
>>>
>>>>
>>>>
>>>> On 6 August 2011 23:40, aditi garg <aditi.garg.6...@gmail.com> wrote:
>>>>
>>>>> A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
>>>>> 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3
>>>>> rows
>>>>> + 16 fr the 4th elemnet so 196
>>>>>
>>>>
>>>> How does it start from 46 and 180 ?
>>>> as per my knowledge, 0x1000 = 4096 and 0x2000 is 8192
>>>>
>>>>
>>>>>
>>>>> On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri <
>>>>> akshaykhatri...@gmail.com> wrote:
>>>>>
>>>>>> how is that 49 bytes and 196 bytes
>>>>>> shouldn't it be 44 and 176 bytes respectively
>>>>>>
>>>>>>
>>>>>> On 6 August 2011 23:26, Ram Chauhan <rb.chau...@gmail.com> wrote:
>>>>>>
>>>>>>> 1049 and 1098
>>>>>>>
>>>>>>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg <
>>>>>>> aditi.garg.6...@gmail.com> wrote:
>>>>>>>
>>>>>>>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>>>>>>>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>>>>>>>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>>>>>>>
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Aditi Garg
>>>>> Undergraduate Student
>>>>> Electronics & Communication Divison
>>>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>>>> Sector 3, Dwarka
>>>>> New Delhi
>>>>>
>>>>>
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>>>
>>>
>>>
>>> --
>>> Aditi Garg
>>> Undergraduate Student
>>> Electronics & Communication Divison
>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>> Sector 3, Dwarka
>>> New Delhi
>>>
>>>
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>
>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
>
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Regards
Rajeev N B <http://www.opensourcemania.co.cc>
"*Winners Don't do Different things , they do things Differently"*
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