Consider the 5 * 64 possible outcomes for the selection of coin and
six flips, each one happening with equal probability. Of those 320
possible outcomes, 4*62 are excluded by knowing that the first 5 flips
are heads. That leaves 64 outcomes with the rigged coin and 2 outcomes
with each of the fair coins, for a total of 72 outcomes. 68 of those
are heads, so the answer to the puzzle is 68 of 72, or 17 of 18.
Don

On Aug 8, 2:36 am, Shachindra A C <sachindr...@gmail.com> wrote:
> @brijesh
>
> *first five times* is mentioned intentionally to mislead i think. I vote for
> 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am wrong.
>
>
>
> On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur <sumitgau...@gmail.com> wrote:
> > (3/5)
>
> > On Aug 7, 10:34 pm, Algo Lover <algolear...@gmail.com> wrote:
> > > A bag contains 5 coins. Four of them are fair and one has heads on
> > > both sides. You randomly pulled one coin from the bag and tossed it 5
> > > times, heads turned up all five times. What is the probability that
> > > you toss next time, heads turns up. (All this time you don't know you
> > > were tossing a fair coin or not).
>
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> --
> Regards,
> Shachindra A C

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