answer is 3/5. 17/80 is the answer for 6 consecutive heads.

On Tue, Aug 9, 2011 at 2:07 AM, Don <dondod...@gmail.com> wrote:

> Consider the 5 * 64 possible outcomes for the selection of coin and
> six flips, each one happening with equal probability. Of those 320
> possible outcomes, 4*62 are excluded by knowing that the first 5 flips
> are heads. That leaves 64 outcomes with the rigged coin and 2 outcomes
> with each of the fair coins, for a total of 72 outcomes. 68 of those
> are heads, so the answer to the puzzle is 68 of 72, or 17 of 18.
> Don
>
> On Aug 8, 2:36 am, Shachindra A C <sachindr...@gmail.com> wrote:
> > @brijesh
> >
> > *first five times* is mentioned intentionally to mislead i think. I vote
> for
> > 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am
> wrong.
> >
> >
> >
> > On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur <sumitgau...@gmail.com>
> wrote:
> > > (3/5)
> >
> > > On Aug 7, 10:34 pm, Algo Lover <algolear...@gmail.com> wrote:
> > > > A bag contains 5 coins. Four of them are fair and one has heads on
> > > > both sides. You randomly pulled one coin from the bag and tossed it 5
> > > > times, heads turned up all five times. What is the probability that
> > > > you toss next time, heads turns up. (All this time you don't know you
> > > > were tossing a fair coin or not).
> >
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> > --
> > Regards,
> > Shachindra A C
>
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