@Raj. Granted that the first flip has a 3/5 probability of getting a head. But if it produces a tail, would you say that the second flip also has a 3/5 probability of getting a head? Or have you learned something from the tail? If you learn something from a tail, why don't you learn something from a head?
Dave On Aug 8, 11:51 pm, raj kumar <megamonste...@gmail.com> wrote: > @all those who gave Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80 > > when it's already given that 5 heads have turned up already then why abut > are you adding that probability > you all are considering it as finding the probability of finding 6 > consecutive heads. > > since all tosses are independent the answer should be 3/5. > the point that 5 heads have turned up already may points that the coin > selected is biased in that case pr(6)=1; > now the answer depends on the interviewer according to me it should be 3/5 > > thanks -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
